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So far, only the particular cases $T_{n,1}$ and $T_{n,2}$ had been studied. We show that $$ \\left(c \\cdot \\frac{k\\cdot 2^k \\cdot n}{\\log k} \\right)^n \\cdot 2^{-\\frac{k(k+3)}{2}} \\cdot k^{-2k-2}\\ \\leq\\ T_{n,k}\\ \\leq\\ \\left(k \\cdot 2^k \\cdot n\\right)^n \\cdot 2^{-\\frac{k(k+1)}{2}} \\cdot k^{-k}, $$ for $k > 1$ and some explicit absolute constant $c > 0$. 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