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Let $G$ be a graph and $L(G)$ be the set of all odd cycle lengths of $G$. We prove that: (1) If $L(G)=\\{3,3+2l\\}$, where $l\\geq 2$, then $\\chi(G)=\\max\\{3,\\omega(G)\\}$; (2) If $L(G)=\\{k,k+2l\\}$, where $k\\geq 5$ and $l\\geq 1$, then $\\chi(G)=3$. These, together with the case $L(G)=\\{3,5\\}$ solved in \\cite{W}, give a complete solution to the general problem addressed in \\cite{W,CS,KRS}. 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