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We prove that for any relation $f \\subseteq \\{0,1\\}^n \\times \\mathcal{R}$ and Boolean function $g:\\{0,1\\}^m \\rightarrow \\{0,1\\}$, $R_{1/3}(f\\circ g^n) = \\Omega(R_{4/9}(f)\\cdot R_{1/2-1/n^4}(g))$, where $f \\circ g^n$ is the relation obtained by composing $f$ and $g$. 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