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It is expressed in terms of the contour-ordered self-energy of the lead with shifted arguments, $\\Sigma^A(\\tau, \\tau') = \\Sigma_L\\bigl(\\tau +\\hbar x(\\tau), \\tau' + \\hbar x(\\tau')\\bigr) - \\Sigma_L(\\tau, \\tau')$, where $\\Sigma_L(\\tau,\\tau')$ is the usual contour-ordered self-energy of the left lead. The cumulants of the energy transferred in a given time $t_M$ from the lead to the center is obtained by taking derivatives. 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