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Built on the work of Morton, in the paper we prove the uniform congruence: $$&\\sum_{x=0}^{p-1}\\Big(\\frac{x^3+mx+n}p\\Big) \\equiv {-(-3m)^{\\frac{p-1}4} \\sum_{k=0}^{p-1}\\binom{-\\frac 1{12}}k\\binom{-\\frac 5{12}}k (\\frac{4m^3+27n^2}{4m^3})^k\\pmod p&\\t{if $4\\mid p-1$,} \\frac{2m}{9n}(\\frac{-3m}p)(-3m)^{\\frac{p+1}4} \\sum_{k=0}^{p-1}\\binom{-\\frac 1{12}}k\\binom{-\\frac 5{12}}k (\\frac{4m^3+27n^2}{4m^3})^k\\pmod p&\\text{if $4\\mid p-3$,}$$ where $(\\frac ap)$ is the Legendre symbol. 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