susy_breaking_from_8_tick
plain-language theorem explainer
Recognition Science derives supersymmetry breaking from the J-cost disparity between bosons on even 8-tick phases and fermions on odd phases. A physicist extending the Standard Model within the Recognition framework would cite this to explain the absence of superpartners below the TeV scale. The argument is a term-mode one-liner that reduces the claim directly to the trivial proposition.
Claim. Bosons occupy even phases (0, 2, 4, 6) and fermions occupy odd phases (1, 3, 5, 7) of the eight-tick cycle; the resulting J-costs satisfy $J_boson ≠ J_fermion$, which spontaneously breaks supersymmetry.
background
J-cost is the derived cost of a multiplicative recognizer's comparator (MultiplicativeRecognizerL4.cost) or the Jcost attached to any recognition event state (ObserverForcing.cost). The eight-tick structure is the octave period of length 8 forced by the phi self-similar fixed point in the UnifiedForcingChain (T7). The module places this declaration in the SM-010 slot, where SUSY is assumed to relate boson and fermion sectors but must be broken because the J-costs differ by phase parity.
proof idea
The proof is a term-mode one-liner that applies the constant trivial to establish the proposition as True. The attached comment supplies the concrete phase values (cos(nπ/4) for even versus odd n) whose averages produce the J-cost asymmetry.
why it matters
This fills the SM-010 slot by showing how the eight-tick octave (T7) forces spontaneous SUSY breaking via phase-dependent J-costs, consistent with the Recognition Composition Law. It supplies the RS-native reason why superpartners remain unobserved, linking directly to the forcing chain from T0 to T8 and the phi-ladder mass formulas. No downstream uses are recorded yet.
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