Pith. sign in
theorem

totalCost_nonneg

proved
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module
IndisputableMonolith.Cosmology.RecognitionEquilibrium
domain
Cosmology
line
189 · github
papers citing
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plain-language theorem explainer

The total recognition cost of a level field on any finite coupling graph is nonnegative. Anyone citing recognition equilibrium, the recognition ledger, or the SM-Lagrangian skeleton uses this as the ground-state lower bound. The proof is a one-line sum-of-nonnegatives argument: each edge contributes a J-cost of a positive phi-power ratio.

Claim. For any $n$, any level field $x:\{0,\ldots,n-1\}\to\mathbb{R}$, and any finite edge set $E\subseteq\{0,\ldots,n-1\}^2$, the total recognition cost satisfies $0\le\sum_{(i,j)\in E} J(\varphi^{x_i-x_j})$, where $J$ is the recognition cost and $\varphi$ is the golden ratio.

background

The module formalizes Phase-7 forward dynamics: a field of recognition levels on a coupling graph evolves by forced pair resolutions that send both endpoints to their mean (the $\sigma=0$, $J$-minimal move). The recognition cost on a positive ratio is $J(r)=(r+r^{-1})/2-1$ (equivalently $\cosh(\log r)-1$), forced unique by the T5 step of the unified forcing chain and the Recognition Composition Law.

On an edge $(i,j)$ the forced ratio is $\varphi^{x_i-x_j}$ with $\varphi>1$ the self-similar fixed point (T6). The total cost is the sum of those edge costs. Upstream, jcost_nonneg already shows $0\le J(r)$ for every $r>0$, with equality only at $r=1$. The present result lifts that pointwise bound to the graph sum.

Local setting (module doc): closed-system descent is a strict Lyapunov drop in level variance until every coupled pair agrees; the zero of total cost is exactly that consensus configuration.

proof idea

One-line term proof. Apply Finset.sum_nonneg to the edge sum that defines total cost. Each summand is a $J$-cost of $\varphi$ raised to a real power; positivity of that base follows from Constants.phi_pos via Real.rpow_pos_of_pos, so the upstream lemma jcost_nonneg supplies $0\le J(\varphi^{\Delta x})$ on every edge. No case split and no graph structure beyond the sum is used.

why it matters

This is the cost half of the recognition ground-state package. Downstream, recognitionEquilibrium packages it as the cost_nonneg field of the equilibrium certificate for every level field and coupling graph, alongside sigma conservation and the exact variance drop. The companion zero-characterization (total cost vanishes iff the field is constant on every edge) then identifies the descent limit with graph consensus.

The same nonnegativity is re-used as a certificate atom in the recognition ledger one-statement (total cost nonnegative, zero iff flat/Minkowski) and in the SM-Lagrangian skeleton certificate (total_nonneg). In framework terms it is the graph-level shadow of T5 $J$-uniqueness: the unique nonnegative cost that vanishes only at ratio one, summed over couplings, forces the cosmogenesis ground state to be consensus rather than some other critical point.

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