Pith. sign in
theorem

orient2_cyclic'

proved
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IndisputableMonolith.Mathematics.DistanceShellMultiplicity
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Mathematics
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plain-language theorem explainer

Cyclic reordering of three planar points from (a,b,c) to (c,a,b) leaves the signed orientation (twice-area determinant) unchanged. Anyone normalizing triangle vertex order in collinearity or distance-shell arguments cites this. The proof is two successive rewrites of the one-step cyclic identity.

Claim. For any three points $a,b,c$ in the Euclidean plane $\mathbb{R}^2$, the signed orientation determinant satisfies $\operatorname{orient}(a,b,c)=\operatorname{orient}(c,a,b)$.

background

The module physicalizes Erdős problem #132: classical distance shells become two-body recognition-energy shells, with ordered-pair multiplicity twice the unordered count. Points live in the visible plane, written as the Euclidean space $\mathbb{R}^2$.

The orientation form is the standard signed twice-area determinant $\operatorname{orient}(a,b,c)=(b_0-a_0)(c_1-a_1)-(b_1-a_1)(c_0-a_0)$. It vanishes precisely on collinear triples and changes sign under odd permutations of the vertices.

The sibling one-step cyclic law already records $\operatorname{orient}(a,b,c)=\operatorname{orient}(b,c,a)$. The present statement is the other generator of the cyclic group on three labels.

proof idea

Term-style tactic proof by two rewrites. Apply the one-step cyclic identity once to send $(a,b,c)$ to $(b,c,a)$, then again to send $(b,c,a)$ to $(c,a,b)$. Equality is transitive, so the two-step cycle preserves orientation. No expansion of the determinant is needed.

why it matters

Downstream, the quadruple-vanishing bridge uses this identity: if the four canonical orientations on ${a,b,c,d}$ vanish, every triple drawn from those four points is collinear. That bridge converts a short list of orientation zeros into the full collinearity predicate needed for diameter-shell and sparse-shell arguments.

In the RS reading, planar orientation controls which ordered pair events sit on the same recognition-energy shell. Keeping cyclic order free of sign flips lets shell-multiplicity counts stay invariant under vertex rotation, which is the bookkeeping step behind the ordered-pair form of the Erdős #132 threshold.

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