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Summing from π‘˜= π‘˜β€² to π‘˜=π‘˜β€²+𝑁 gives βˆ‘ (𝑓(π‘˜)βˆ’π‘“(π‘˜+1)) π‘˜β€²+𝑁 π‘˜=π‘˜β€² β‰₯ 𝛾𝑓 βˆ‘ πœƒ(π‘˜) π‘˜β€²+𝑁 π‘˜=π‘˜β€²

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