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(61) Since the above holds for alli∈[d], we know that 0 = Z ∇x0 PX0|x1(x0)dx0 =E X0|x1 ∇x0 logP X0|x1(x0) =E X0|x1 − α β x0 − x1√α +s ⋆ 0(x0)

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