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1 + sin2 ωtp 1 +γ 2 ⊥tp γ2 K + 1 2γ2 K ! ×arcsinhγ ⊥tp − γ⊥tp q 1 +γ 2 ⊥tp 2γ2 K (1 + 2 sin2 ωtp)   . (A3) 15 In particular, g(0,0) = 3 2γK

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