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George E · 1965

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math.NT 1

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2025 1

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CONDITIONAL 1

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On the Lebesgue-Nagell equation $x^2-2 = y^p$

math.NT · 2025-07-16 · conditional · novelty 7.0

For the equation x^2 - 2 = y^p, the authors prove the only solutions for p>911 are y = -1, and any nontrivial solution has y > 10^1000.

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  • On the Lebesgue-Nagell equation $x^2-2 = y^p$ math.NT · 2025-07-16 · conditional · none · ref 1

    For the equation x^2 - 2 = y^p, the authors prove the only solutions for p>911 are y = -1, and any nontrivial solution has y > 10^1000.