pith. sign in

(69), we have e−ik∗ 1 L = k∗ 1 −l−ic ′∗/2 k∗ 1 −l+ic ′∗/2 ,(77) ∴e ik∗ 1 L = k∗ 1 −l+ic ′∗/2 k∗ 1 −l−ic ′∗/2 .(78) On the other hand, from Eq

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