No universal multiplicative FDR bound holds for Benjamini-Hochberg under Gaussian dependence: worst-case FDR/q diverges like sqrt(log(1/q)), with exact constants in natural cases.
Anat Reiner-Benaim
1 Pith paper cite this work. Polarity classification is still indexing.
1
Pith paper citing it
fields
math.ST 1years
2026 1verdicts
ACCEPT 1representative citing papers
citing papers explorer
-
How Much Can Gaussian Dependence Inflate the Benjamini-Hochberg Procedure's FDR?
No universal multiplicative FDR bound holds for Benjamini-Hochberg under Gaussian dependence: worst-case FDR/q diverges like sqrt(log(1/q)), with exact constants in natural cases.