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∂g ∂θ θ⋆(ϕ),ϕ #−1 ∂g ∂ϕ θ⋆(ϕ),ϕ . Since ∂g ∂θ = ∂2Linner ∂θ 2 , ∂g ∂ϕ = ∂2Linner ∂θ∂ϕ , we get dθ⋆ dϕ ϕ =−

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2026 1

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CONDITIONAL 1

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