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2024 1

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Almost-full transversals in equi-$n$-squares

math.CO · 2024-12-10 · accept · novelty 8.0

There exists epsilon > 0 such that every equi-n-square contains n - n^(1-epsilon) disjoint transversals of size n - n^(1-epsilon), while some equi-n-squares have no transversal larger than n - (1/(2*sqrt(2)) + o(1))*sqrt(n).

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  • Almost-full transversals in equi-$n$-squares math.CO · 2024-12-10 · accept · none · ref 5

    There exists epsilon > 0 such that every equi-n-square contains n - n^(1-epsilon) disjoint transversals of size n - n^(1-epsilon), while some equi-n-squares have no transversal larger than n - (1/(2*sqrt(2)) + o(1))*sqrt(n).