The paper proves Kolokolnikov's conjecture: every graph on n vertices with at most 2n-4 edges has algebraic connectivity at most 2, so K_{2,n-2} is a maximizer.
Maximizing Algebraic Connectivity with $2(n-2)$ Edges: The Large Vertex Number Case
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abstract
Kolokolnikov conjectured that, among finite simple graphs on $n$ vertices with exactly $2(n-2)$ edges, the complete bipartite graph $K_{2,n-2}$ maximizes algebraic connectivity. We prove the conjectured statement for every $n\ge123$: every such graph has algebraic connectivity at most $2$, while $K_{2,n-2}$ attains $2$. The proof begins with explicit Rayleigh-quotient certificates that exclude several local configurations from a hypothetical counterexample. A global degree count then controls the number and total excess of vertices of degree at least $5$ and bounds the edge excess of the subgraph induced by vertices of degree at most $4$. A Moore-type breadth-first-search criterion uses this excess to guarantee a short cycle, while a spectral criterion excludes cycles in the same length range. An explicit arithmetic estimate shows that the two criteria apply simultaneously once $n\ge123$. A Lean formalization covering every $n\ge4$, including the complementary range $4\le n\le122$, has been produced with MerLean and checked by the Lean kernel; the present paper gives a self-contained mathematical account of the large-order component.
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On a conjecture of Kolokolnikov on algebraic connectivity
The paper proves Kolokolnikov's conjecture: every graph on n vertices with at most 2n-4 edges has algebraic connectivity at most 2, so K_{2,n-2} is a maximizer.