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(A9) The solution for ˆgK 2 is different from ˆgR(A) 2 because it satisfies the different normalization condition: ˆgR ϵ+δˆgK + ˆgK ϵ+δˆgA +δˆgKˆgA ϵ− +δˆgRˆgK ϵ− = 0

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