An observation: cut-off of the weight w does not increase the A_{p₁, p₂}-"norm'' of w
classification
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keywords
normconsidercasecut-offcut-offsespeciallygeneralizedgreater
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We consider weights $w$ and their cut-offs: $w_a(t)=w(t)$ if $w(t)\le a$ and $w_a(t)=a$ if $w(t)> a$. We consider a generalized $A_p$-``norm'' and prove that the ``norm'' of $w_a$ is not greater then the ``norm'' of $w$. Our proof in the case $w\in A_2$ is especially simple.
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