pith. sign in

arxiv: 1203.6380 · v1 · pith:HQAGD3NYnew · submitted 2012-03-28 · 🧮 math.GM

The Diophantine Equation arctan(1/x)+arctan(m/y)= arctan(1/k)

classification 🧮 math.GM
keywords arctanpositiveequationintegerarticlediophantineequalitygiven
0
0 comments X
read the original abstract

In the fall 2011 issue of the Journal'Mathematics and Computer Education', author Unal Hasan, in the one page article "Proof without Words", gives a purely geometric proof of the equality, arctan(1/3)+ arctan(1/7) = arctan(1/2) (1) (See reference [1]) Now consider the two-variable diophantine equation(x and y being positive integer variables), arctan(1/x) + arctan(m/y) = arctan(1/k) (2), where m and k are given or fixed positive integers with gcd(m,k^2+1)=1;and also with gcd(m,y)=1. Equality (1) then says that the pair (3,7)is a positive integer solution to (2) in the case m=1=k. We prove, in Theorem1(a,) that equation (2) has exactly N(number of positive divisors of k^2+1) distinct positive integer solutions (x,y), given by x=k+m(k^2+1)/d, y=km+d; d a positive divisor of k^2+1. As a result of Th.1, we list nine arctangent equalities in Section5 of this article, including inequality (1) above.

This paper has not been read by Pith yet.

discussion (0)

Sign in with ORCID, Apple, or X to comment. Anyone can read and Pith papers without signing in.