Strongly productive ultrafilters on semigroups
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🧮 math.LO
math.GR
keywords
productivesemigroupstronglyfoundedsemilatticeultrafilterwellanswering
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We prove that if S is a commutative semigroup with well founded universal semilattice or a solvable inverse semigroup with well founded semilattice of idempotents, then every strongly productive ultrafilter on S is idempotent. Moreover we show that any very strongly productive ultrafilter on the free semigroup with countably many generators is sparse, answering a question of Hindman and Legette Jones.
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