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arxiv: 1505.07688 · v1 · pith:Q3DW4ETJnew · submitted 2015-05-28 · 🧮 math.CO

Anti-magic labeling of regular graphs

classification 🧮 math.CO
keywords antimagicgraphsregulardegreeevengraphnon-bipartiteproblem
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A graph $G=(V,E)$ is antimagic if there is a one-to-one correspondence $f: E \to \{1,2,\ldots, |E|\}$ such that for any two vertices $u,v$, $\sum_{e \in E(u)}f(e) \ne \sum_{e\in E(v)}f(e)$. It is known that bipartite regular graphs are antimagic and non-bipartite regular graphs of odd degree at least three are antimagic. Whether all non-bipartite regular graphs of even degree are antimagic remained an open problem. In this paper, we solve this problem and prove that all even degree regular graphs are antimagic. The paper was submitted to December 2014 by Journal of Graph Theory.

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