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arxiv: 1704.03062 · v2 · pith:O34DFHUVnew · submitted 2017-04-10 · 🧮 math.FA · cs.DM· math.CO· math.MG

Controlling Lipschitz functions

classification 🧮 math.FA cs.DMmath.COmath.MG
keywords mathbbcontrollingsequenceconjectureeverylipschitzprovealready
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Given any positive integers $m$ and $d$, we say the a sequence of points $(x_i)_{i\in I}$ in $\mathbb R^m$ is {\em Lipschitz-$d$-controlling} if one can select suitable values $y_i\; (i\in I)$ such that for every Lipschitz function $f:\mathbb R^m\rightarrow \mathbb R^d$ there exists $i$ with $|f(x_i)-y_i|<1$. We conjecture that for every $m\le d$, a sequence $(x_i)_{i\in I}\subset\mathbb R^m$ is $d$-controlling if and only if $$\sup_{n\in\mathbb N}\frac{|\{i\in I\, :\, |x_i|\le n\}|}{n^d}=\infty.$$ We prove that this condition is necessary and a slightly stronger one is already sufficient for the sequence to be $d$-controlling. We also prove the conjecture for $m=1$.

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