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arxiv: 1806.06315 · v5 · pith:6AISCAIGnew · submitted 2018-06-16 · 🧮 math.CO

ON (triangle, 1)-GRAPHS

classification 🧮 math.CO
keywords lambdagrapheveryexactlygraphstherebelongsbyproduct
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Let $G = (V, E)$ be a graph and $\lambda $ a non-negative integer. A graph $G$ is called a $(\lambda, 1)$-{\em graph} if $ (c0)$ $G$ is neither a complete graph no an edge-empty graph, $ (c1)$ every edge in $G$ belongs to exactly $\lambda$ triangles, and $(c2)$ every two non-adjacent vertices in $G$ are the end-vertices of exactly one two-edge path in $G$. It turns out that there are infinitely many feasible 4-tuples $(v, d, \lambda, 1)$ with $\lambda \ge 1$. On the other hand (and this is our main result), there is no $(v, d, \lambda, 1)$-graphs with $\lambda \ge 1$. As a byproduct, we obtain a generalization of the classical Friendship Theorem.

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