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arxiv: 1902.02378 · v1 · pith:6BQ44QL2new · submitted 2019-02-06 · 🧮 math.GR

Retracts of free groups and a question of Bergman

classification 🧮 math.GR
keywords textrmeveryretractranksubgroupbergmanfreeprove
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Let $F_n$ be a free group of finite rank $n \geq 2$. We prove that if $H$ is a subgroup of $F_n$ with $\textrm{rk}(H)=2$ and $R$ is a retract of $F_n$, then $H \cap R$ is a retract of $H$. However, for every $m \geq 3$ and every $1 \leq k \leq n-1$, there exist a subgroup $H$ of $F_n$ of rank $m$ and a retract $R$ of $F_n$ of rank $k$ such that $H \cap R$ is not a retract of $H$. This gives a complete answer to a question of Bergman. Furthermore, we provide positive evidence for the inertia conjecture of Dicks and Ventura. More precisely, we prove that $\textrm{rk}(H \cap \textrm{Fix}(S)) \leq \textrm{rk}(H)$ for every family $S$ of endomorphisms of $F_n$ and every subgroup $H$ of $F_n$ with $\textrm{rk}(H) \leq 3$.

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  1. On verbally closed subgroups of free solvable groups

    math.GR 2019-06 unverdicted novelty 5.0

    Sufficient conditions are established for verbally closed subgroups of free solvable groups to be retracts and therefore algebraically closed.