On zero-sum problems over metacyclic groups C_n rtimes_s C₂
Pith reviewed 2026-05-17 06:51 UTC · model grok-4.3
The pith
The remaining case for Gao's constant E(G) in metacyclic groups C_n ⋊_s C_2 is resolved, completing the full determination for the class.
A machine-rendered reading of the paper's core claim, the machinery that carries it, and where it could break.
Core claim
For the metacyclic group G = C_{3n_2} ⋊_s C_2 under the conditions n_2 ≠ 1, gcd(n_2, 6) = 1, s ≡ -1 mod 3, and s ≡ 1 mod n_2, the Gao constant E(G) is determined and the inverse problem is solved, as stated in Theorem 1.2. This completes the settlement for all groups of the form C_n ⋊_s C_2.
What carries the argument
The specific case analysis for sequences in G = C_{3n_2} ⋊_s C_2 relying on the arithmetic conditions of n and the congruences of s to prove existence of product-one subsequences of length |G|.
If this is right
- The inverse problem for E(G) is fully resolved for the entire family, giving the structure of all extremal sequences.
- No exceptions remain in the determination of Gao's constant for metacyclic groups of this type.
- The result allows a uniform description of E(G) across all possible twisting parameters s with s squared congruent to one modulo n.
Where Pith is reading between the lines
- This complete classification could serve as a foundation for investigating product-one sequences in other families of non-abelian groups.
- Computational checks for small n_2 might independently verify the case distinctions used in the proof.
Load-bearing premise
The proof depends on the arithmetic conditions that n equals three times n_2 where n_2 is greater than one and coprime to six, together with s being congruent to minus one modulo three and congruent to one modulo n_2.
What would settle it
The discovery of a sequence of length 2|G|-2 over one of these specific groups that has no product-one subsequence of length |G| would disprove the claimed value of the Gao constant.
read the original abstract
Let $G$ be a finite group. A finite collection of elements from $G$, where the order is disregarded and repetitions are allowed, is said to be a product-one sequence if its elements can be ordered such that their product in $G$ equals the identity element of $G$. Then, the Gao's constant $\mathsf E (G)$ of $G$ is the smallest integer $\ell$ such that every sequence of length at least $\ell$ has a product-one subsequence of length $|G|$. For a positive integer $n$, we denote by $C_n$ a cyclic group of order $n$. Let $G = C_n \rtimes_s C_2$ with $s^2\equiv 1\pmod n$ be a metacyclic group. The direct and inverse problems of $\mathsf E (G)$ were settled recently, except for the case that $G=C_{3n_2}\rtimes_s C_2$ with $n_2\neq 1$, $\gcd(n_2,6)=1$, $s\equiv -1 \pmod 3$, and $s\equiv 1\pmod {n_2}$. In this paper, we complete the remaining case and hence for all metacyclic groups of the form $G=C_n \rtimes C_2$, the Gao's constant and the associated inverse problem are now fully settled (see Theorem 1.2).
Editorial analysis
A structured set of objections, weighed in public.
Referee Report
Summary. The paper claims to resolve the remaining open case for Gao's constant E(G) and the associated inverse problem in metacyclic groups G = C_n ⋊_s C_2, specifically when n = 3n_2 with n_2 ≠ 1, gcd(n_2, 6) = 1, s ≡ -1 mod 3 and s ≡ 1 mod n_2. By handling this case via combinatorial arguments and case analysis on coset distributions, the authors assert that E(G) and the extremal sequences are now fully determined for every group of this form (Theorem 1.2).
Significance. If the case analysis holds, the result completes the determination of E(G) for the entire family of metacyclic groups C_n ⋊_s C_2, building on prior resolutions of other cases and providing a uniform description of product-one subsequences of length |G|.
major comments (2)
- [Abstract and Theorem 1.2] Abstract and Theorem 1.2: The global settlement claim requires that the arithmetic restrictions (n = 3n_2, s ≡ -1 mod 3, s ≡ 1 mod n_2) together with previously settled cases partition all pairs (n, s) satisfying s^2 ≡ 1 mod n. No explicit verification of this partition is provided, leaving open the possibility that some s lie outside the stated classes.
- [Section 4] Section 4 (main case analysis): The proof proceeds by exhaustive distribution of elements from the two cosets and invokes auxiliary lemmas that exploit the specific congruences s ≡ -1 mod 3 and s ≡ 1 mod n_2 to bound zero-sum-free sequences. It is not shown that these lemmas remain valid uniformly for all n_2 > 1 with gcd(n_2, 6) = 1, particularly when n_2 is composite.
minor comments (2)
- [Preliminaries] The notation for sequences and subsequences in the preliminaries could be aligned more closely with standard zero-sum literature to improve readability.
- [Introduction] A short table summarizing the values of E(G) across all cases (including the new one) would help readers see the complete picture.
Simulated Author's Rebuttal
We thank the referee for the careful reading of our manuscript and the constructive comments. We address the major comments point by point below and indicate the revisions we plan to make.
read point-by-point responses
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Referee: [Abstract and Theorem 1.2] Abstract and Theorem 1.2: The global settlement claim requires that the arithmetic restrictions (n = 3n_2, s ≡ -1 mod 3, s ≡ 1 mod n_2) together with previously settled cases partition all pairs (n, s) satisfying s^2 ≡ 1 mod n. No explicit verification of this partition is provided, leaving open the possibility that some s lie outside the stated classes.
Authors: We appreciate this observation. The partition of cases is based on the possible automorphisms s satisfying s^2 ≡ 1 mod n and the conditions under which the group is metacyclic of this form, with prior papers having handled all cases except the one specified. However, to make this explicit and remove any ambiguity, we will add a clarifying remark in the revised version of the paper, immediately following the statement of Theorem 1.2, that verifies the cases are exhaustive by considering the possible residues of s modulo 3 and modulo n_2, cross-referenced with the literature on previously settled cases. revision: yes
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Referee: [Section 4] Section 4 (main case analysis): The proof proceeds by exhaustive distribution of elements from the two cosets and invokes auxiliary lemmas that exploit the specific congruences s ≡ -1 mod 3 and s ≡ 1 mod n_2 to bound zero-sum-free sequences. It is not shown that these lemmas remain valid uniformly for all n_2 > 1 with gcd(n_2, 6) = 1, particularly when n_2 is composite.
Authors: The proofs of the auxiliary lemmas rely solely on the congruences s ≡ -1 (mod 3) and s ≡ 1 (mod n_2), together with the assumption that gcd(n_2, 6) = 1. These conditions ensure that 3 does not divide n_2 and that n_2 is odd, allowing the subgroup generated by the relevant elements to have the necessary properties for the zero-sum bounds. The arguments are combinatorial and do not require n_2 to be prime; they hold for any integer n_2 satisfying the gcd condition, whether prime or composite. To clarify this for the reader, we will insert a brief explanatory sentence in Section 4 noting the uniformity of the lemmas with respect to the compositeness of n_2. revision: yes
Circularity Check
No significant circularity; remaining case settled by direct combinatorial case analysis.
full rationale
The paper completes the remaining arithmetic case for G = C_{3n_2} ⋊_s C_2 by exhaustive case analysis on coset distributions and zero-sum-free sequences, using auxiliary lemmas that exploit the stated congruences on n_2 and s. Prior settlements for other cases are cited as external background rather than as load-bearing self-references within the new derivation. No equations reduce by construction to fitted inputs, no uniqueness theorems are imported from the same authors' prior work to force the result, and the central claim does not rename or smuggle an ansatz. The derivation is self-contained against the combinatorial structure of the group and the given restrictions.
Axiom & Free-Parameter Ledger
axioms (2)
- standard math Finite groups satisfy the usual axioms of associativity, identity, and inverses.
- domain assumption The semidirect product C_n ⋊_s C_2 is well-defined when s^2 ≡ 1 mod n.
Reference graph
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