Complexity of Inverting the Euler Function
read the original abstract
We present an algorithm to invert the Euler function $\phi(m)$. The algorithm, for a given $n \geq 1$, in polynomial time ``on average'', finds the set $\Psi(n)$ of all solutions $m$ to $\phi(m) = n$. In fact, in the worst case, $\Psi(n)$ is exponentially large, and cannot be computed in polynomial time. In the opposite direction, we show, under a widely accepted number theoretic conjecture, that there is a polynomial time reduction of the Partition Problem, an NP-complete problem, to the problem of deciding whether $\phi(m) = n$ has a solution for a small set of integers n. This shows that the problem of deciding whether a given finite set of integers S contains a totient is NP-complete. A totient is an integer n that lies in the image of the phi function; that is, an integer n for which there exists an integer m solving phi(m) = n. Finally, we establish close links between of inverting the Euler function and the integer factorization problem.
This paper has not been read by Pith yet.
discussion (0)
Sign in with ORCID, Apple, or X to comment. Anyone can read and Pith papers without signing in.