REVIEW 1 major objections 6 minor 12 references
Asymptotic expansions for the reciprocal Hardy-Littlewood logarithmic integrals
T0 review · 1 major / 6 minor · reviewed 2026-08-11 · deepseek-v4-flash
Pith's one-line read For every positive integer k, the reciprocal of the k-th Hardy-Littlewood logarithmic integral has an explicit full asymptotic expansion in powers of 1/log x, with coefficients given by a recurrence that generalizes the indecomposable…
desk verdict A correct, modest generalization of Panaitopol's reciprocal li expansion; the proof has a repairable rigor gap and a sign typo, but the main result stands. read the letter →
The pith
A machine-rendered reading of the paper's core claim, the machinery that carries it, and where it could break.
The reading
What carries the argument
The load-bearing object is the coefficient sequence $a_n^{(k)}$ together with the generating-function identity of Proposition 2.2: $$1 - (k-1)!\left(\sum_{n\ge 0}(n+k-1)!\,x^n\right)^{-1} = kx + \sum_{n\ge 1} $a_n^{{(k)}}$ $x^{{n+1}}$$$ as formal power series. This identity connects the recurrence to the reciprocal of a factorial series; when $x$ is replaced by $1/\log x$ and the factorial series is read through the asymptotic expansion of the exponential integral, it becomes the correction series in the expansion of $1/\mathrm{li}_k(x)$. The sequence's $k=1$ case counts indecomposable permutations, and the paper shows the higher-$k$ sequences play the same combinatorial role for the higher logarithmic integrals.
What would settle it
Evaluate $1/\mathrm{li}_2(x)$ numerically to high precision at $x=10^j$ for a fixed truncation order $N$ and check whether $\frac{(\log x)^{N+2}}{x}\left(1/\mathrm{li}_2(x) - \text{partial sum}_N(x)\right)$ stays bounded as $j$ grows. If it does not, the asserted asymptotic expansion for $k=2$ is false; checking the first coefficients against Proposition 2.2 would catch algebraic errors.
Extended reading notes
Core claim
The main result, Theorem 2.7, states that for each $k \in \mathbb{Z}^+$, as $x \to \infty$, $$\frac{1}{\mathrm{li}_k(x)} \sim \frac{(\log x)^k}{x}\left(1 - \frac{k}{\log x} - \sum_{n\ge 1}\frac{$a_n^{{(k)}}$}{(\log x)^{n+1}}\right),$$ where the coefficients $a_n^{(k)}$ are fixed by the recurrence $$(k-1)!\,$a_n^{{(k)}}$ = (n+k)! - k(n+k-1)! - \sum_{m=0}^{n-2} (n-m+k-2)!\,a_{m+1}^{(k)},$$ with $a_0^{(k)}=1$. The proof starts from a formal power-series identity for the generating function of these coefficients and transfers it into an asymptotic statement via the standard asymptotic expansion of the exponential integral and a change of variables. When $k=1$, the coefficients count indecomposable permutations and the expansion reduces to the known reciprocal prime-counting expansion.
Load-bearing premise
The load-bearing assumption is that substituting the divergent series for the exponential integral by its asymptotic expansion, and then reciprocating and re-expanding termwise, preserves the final asymptotic expansion; this operation is used in the proof of Theorem 2.7 without being stated or proved.
Editorial extensions
If this is right
- For every $k$, the reciprocal $1/\mathrm{li}_k(x)$ now has a complete, explicitly computable asymptotic series in powers of $1/\log x$, with integer coefficients fixed by an elementary recurrence.
- Setting $k=1$ recovers the known expansion for the reciprocal prime counting function, since $\mathrm{li}(x)-\pi(x)$ is much smaller than any term in the asymptotic sequence.
- The coefficients $a_n^{(k)}$ generalize the indecomposable permutation counts, giving sequences originally studied combinatorially a role in the analytic theory of prime distributions.
- The expansion supplies the correction terms needed if the first Hardy-Littlewood conjecture is strengthened from a leading-order asymptotic to a full asymptotic expansion for prime $k$-tuple counts.
Reading between the lines
- If the first Hardy-Littlewood conjecture is ever promoted to a full asymptotic expansion for prime $k$-tuple counts, the coefficients $a_n^{(k+1)}$, up to the singular-series constant of the tuple, are the natural correction coefficients; this is an extrapolation, since the paper only says the expansion is 'salient' to the conjecture.
- The $k=1$ equivalence between $1/\mathrm{li}(x)$ and $1/\pi(x)$ uses an error bound much larger than the individual terms of the new series, so comparing the expansion with numerical values of $\mathrm{li}_k(x)$ directly would be a sharper test than comparing with prime counts.
- The recurrence likely admits a combinatorial interpretation for every $k$, since its $k=1$ case counts indecomposable permutations; such an interpretation would give an independent, purely finite check of the analytic coefficients.
Editorial analysis
A structured set of objections, weighed in public.
Referee Report
Summary. This paper defines, for every positive integer k, an integer sequence (a_n^{(k)}) by the recurrence in Definition 2.1 (with a_0^{(k)} = 1) and proves Proposition 2.2, a formal power series identity generalizing Comtet's generating function for indecomposable permutations: 1 − (k−1)! (∑_{n≥0} (n+k−1)! x^n)^{-1} = kx + ∑_{n≥1} a_n^{(k)} x^{n+1}. Proposition 2.4 (the standard asymptotic expansion of the exponential integral) and Lemma 2.6 (a reduction of li_k to li) are then combined with this identity to prove Theorem 2.7, which asserts the complete asymptotic expansion 1/li_k(x) ∼ (log x)^k/x (1 − k/log x − ∑_{n≥1} a_n^{(k)}/(log x)^{n+1}) for the reciprocal of the k-th Hardy-Littlewood logarithmic integral. For k = 1 the expansion reduces to the known expansion of 1/li(x), and through the remark following Proposition 1.2 to Panaitopol's expansion for 1/π(x). The Hardy-Littlewood application is presented as motivation, with an explicit caveat that the result only provides auxiliary information for a possible strengthening of Conjecture 1.3.
Significance. If the proof is completed as suggested in Major Comment 1, the main theorem is a correct, parameter-free, complete asymptotic expansion whose coefficients come from an independently defined combinatorial recurrence; there is no circularity and no fitted constant. The k = 2 case matches the direct integration-by-parts expansion, the k = 1 case reproduces the Comtet/Panaitopol system, and the coefficient sequences are identified with OEIS entries; these are genuine strengths that make the expansion a concrete, checkable target for any future strengthening of the first Hardy-Littlewood conjecture. The significance of the result is moderate: it is a clean unification of a classical combinatorial generating function with the asymptotic theory of logarithmic integrals, and the paper's claims about the conjecture are appropriately hedged. The principal weakness is the unstated asymptotic-manipulation step in the proof of Theorem 2.7, which is the load-bearing point of the paper and needs a short lemma or a precise citation.
major comments (1)
- [Theorem 2.7, proof (step after 'Proposition 2.4 gives the relation A(1/x) ∼ xe^{−x}Ei(x); thus, ...')] This step substitutes the divergent formal series A(1/x) = ∑_{n≥0} n!x^{−n} by the function xe^{−x}Ei(x) inside the rational expression (k−1)!x^{1−k}/(A(1/x) − ∑_{i=0}^{k−2} i!x^{−i}) and then takes a reciprocal, without any stated justification. As written, the line is a formal manipulation of a divergent series, not a consequence of Definition 1.1. What is needed is the standard theorem that Poincaré asymptotic expansions are preserved under rational combinations when the denominator's leading asymptotic term is nonzero — here the denominator has leading term (k−1)!/x^{k−1} — and this theorem is neither stated, nor proved, nor cited. This step is load-bearing, because it is what turns the formal identity of Proposition 2.2 into the asymptotic statement. I verified the conclusion independently: for k = 2 the theorem's expansion reproduces 1/li_2(x) ∼ (log x)^2/x (1 − 2/log x − 2/(log x)^2 − 8/(log x)^3 − 44/(log x)^4 − ···) from the direct expansion of li_2, so the gap is a rigor gap rather than an error. The fix is local: add a lemma (if f(x) ∼ ∑ c_n x^{−n} with c_0 ≠ 0, then 1/f(x) admits the formal reciprocal expansion, and rational expressions inherit expansions by substitution), with a short proof or a precise citation, and verify its hypotheses for the specific denominator used.
minor comments (6)
- [Proposition 2.2, proof] The first displayed line reads '(k−1)!I_k(x) = k!x − ∑_{n≥1}(k−1)!a_n^{(k)}x^{n+1}', but since I_k(x) = kx + ∑_{n≥1}a_n^{(k)}x^{n+1} the sign before the sum should be '+'; the subsequent line is consistent with the corrected sign, so this is a typo, but it is very confusing.
- [Theorem 2.7, statement] The asymptotic sequence with respect to which the expansion holds is implicit; it should be stated explicitly (e.g., {x^{−1}(log x)^{k−m}}_{m≥0}) so that the statement conforms to Definition 1.1.
- [Theorem 2.7, proof] The notation 'A(1/x) ∼ xe^{−x}Ei(x)' is an abuse of notation, since A(1/x) diverges for every finite nonzero x; it would be clearer to write that xe^{−x}Ei(x) has the asymptotic expansion ∑_{n≥0} n!x^{−n}.
- [Introduction, remark after Proposition 1.2] The sentence 'Proposition 1.2 may be quickly obtained ... by following the k = 1 case of the proof of Theorem 2.7' refers forward to a theorem proved later; consider rephrasing, for example, 'by following the proof of Theorem 2.7 in Section 2 with k = 1'.
- [References / novelty] Please confirm that the k ≥ 2 cases of Theorem 2.7 do not already appear in [5] or in the literature following [11]; if they do, the abstract's novelty claim should be adjusted accordingly.
- [General] There are several typographical artifacts (e.g., 'C onsequently' in the abstract, 's eries' in the first paragraph of Section 1); a careful proofread is advised.
Circularity Check
No circularity: the coefficient sequence is independently defined by a recurrence, and the proof derives the asymptotic expansion from the standard DLMF expansion of Ei, with no fitted parameter or self-citation chain.
full rationale
The paper's central claim, Theorem 2.7, gives an asymptotic expansion for 1/li_k(x) whose coefficients a_n^(k) are defined by the independent recurrence in Definition 2.1, involving only factorials and earlier coefficients, with no reference to li_k(x), Ei(x), or the target asymptotic expansion. Proposition 2.2 proves a formal power series identity relating these coefficients to the reciprocal of the series sum (n+k-1)! x^n. The proof of Theorem 2.7 then combines this formal identity with the standard, externally cited asymptotic expansion Ei(x) ~ e^x/x sum n!/x^n (Proposition 2.4, from DLMF) and the elementary integration-by-parts identity of Lemma 2.6. The coefficients are not fitted to any data from the logarithmic integrals, and no parameter is renamed as a prediction. The only notable gap is that the proof substitutes the divergent formal series A(1/x) with its Poincaré asymptotic expansion and then manipulates reciprocals without explicitly stating the standard theorem on asymptotic expansions of reciprocals; this is a rigor gap, not circularity. There are no self-citations at all, and no load-bearing appeal to the authors' prior work. The result is therefore self-contained relative to its stated external inputs, and the circularity score is 0.
Assumptions & free parameters
assumptions (3)
- domain assumption Asymptotic power series are closed under addition, multiplication, and reciprocation, and the asymptotic expansion of a reciprocal is the formal reciprocal of the asymptotic expansion.
- standard math Standard asymptotic expansion of the exponential integral: Ei(x) ~ e^x/x sum_{n>=0} n!/x^n as x -> infinity.
- standard math Classical estimate of de la Vallee Poussin: pi(x) = li(x) + O(x exp(-a sqrt(log x))) for some a > 0.
Cite this review
Pith. "Pith review of Asymptotic expansions for the reciprocal Hardy-Littlewood logarithmic integrals." pith.science (2026). https://pith.science/paper/2HTN6L2G
@misc{pith2026241219866,
author = {Pith},
title = {Pith review of: Asymptotic expansions for the reciprocal Hardy-Littlewood logarithmic integrals},
year = {2026},
howpublished = {\url{https://pith.science/paper/2HTN6L2G}},
note = {Machine review of arXiv:2412.19866}
}
read the original abstract
Defining a family of recurrences, we generalize Comtet's formula for the generating function of the enumeration of indecomposable permutations. Consequently, we generalize Panaitopol's asymptotic expansion for the prime counting function, obtaining asymptotic expansions salient to the first Hardy-Littlewood conjecture.
Reference graph
Works this paper leans on
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Reviewed August 11, 2026 · model on record in the stance chip above.
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