REVIEW 3 major objections 3 minor 1 cited by
Nordhaus-Gaddum inequality for the spectral radius of a graph of order $n$
T0 review · 3 major / 3 minor · reviewed 2026-08-07 · deepseek-v4-flash
Pith's one-line read Complete split graphs maximize the spectral radius of a graph plus its complement, for every order.
desk verdict Settles a 2007 Nordhaus-Gaddum conjecture for all n; the main argument holds up, but Lemma 2.1's universality is asserted rather than proved. read the letter →
The pith
A machine-rendered reading of the paper's core claim, the machinery that carries it, and where it could break.
The reading
What carries the argument
The carrying object is the staircase class $S^*_s(n)$: symmetric zero-diagonal $0$-$1$ matrices whose $1$'s fill a staircase shape, with corner conditions $a_{12}=1$ and $a_{n-1,n}=0$. The proof begins with the structural lemma that every extremal graph has a vertex ordering whose adjacency matrix lies in this class. For such a matrix $A$, three integer parameters $c,v,s$ record where the staircase stops, and mirrored parameters $\bar c,\bar v,\bar s$ are read from the reflected complement. A row-sum bound supplies the closed upper estimate $\rho(A)\le \phi(A)$ in terms of $(c,v,s)$, and a sequence of local staircase moves shows that no candidate can beat the complete split form. The final comparison is reduced to a quartic polynomial $g(x)$ that is increasing on the relevant interval, with one exceptional parameter triple excluded by a rooted-matrix bound and the characteristic polynomial of an explicit $6\times 6$ matrix.
What would settle it
For a fixed small $n$, exhaustively compute $\rho(G)+\rho(\bar G)$ over all unlabeled graphs of that order and check that the maximum agrees with the right-hand side of (4.3) and is attained only by the named complete split graphs; a single counterexample would refute the claim. Alternatively, in the exceptional case $(n,c,\bar c)=(3k+2,2k+1,2k+1)$, evaluate the spectral radius of the explicit $6\times 6$ matrix $M$ in Section 7: if it ever reaches $\rho_0=4k+1$, the exclusion argument fails.
Extended reading notes
Core claim
The paper's central claim is that the conjecture holds in full: among all simple graphs of order $n\ge 3$, the sum $\rho(G)+\rho(\bar G)$ is maximized by the complete split graph $K_{\lfloor n/3\rfloor}\vee N_{\lceil 2n/3\rceil}$ and by its complement, and when $n\equiv 2\pmod 3$ also by $K_{\lceil n/3\rceil}\vee N_{\lfloor 2n/3\rfloor}$ and its complement. A complete split graph is formed by joining a clique to an independent set with all possible edges, so its complement is a disjoint union of an independent set and a clique. The proof gives the exact maximum value in closed form as (4.3) and shows that the equality cases are exactly these graphs up to complementation. A direct corollary is the uniform bound $\rho(G)+\rho(\bar G)\le (4/3)n+1/3$.
Load-bearing premise
The proof depends on the structural lemma that every extremal graph, after relabeling, has its adjacency matrix in the staircase class; if some extremal graph lacked such an ordering, the whole reduction would only cover a subclass of candidates.
Editorial extensions
If this is right
- The exact extremal value of $\rho(G)+\rho(\bar G)$ is known for every $n$ through the closed formula (4.3), so the maximum no longer needs to be estimated asymptotically.
- Every extremal graph is classified: it is the complete split graph $K_{\lfloor n/3\rfloor}\vee N_{\lceil 2n/3\rceil}$, its complement, and additionally $K_{\lceil n/3\rceil}\vee N_{\lfloor 2n/3\rfloor}$ or its complement when $n\equiv 2\pmod 3$.
- The uniform bound $\rho(G)+\rho(\bar G)\le (4/3)n+1/3$ follows, verifying the previously conjectured $4n/3+O(1)$ form.
- Because the proof is purely linear algebraic, it covers all $n$ uniformly and does not rely on analytic large-$n$ methods.
Reading between the lines
- The same staircase-and-parameter strategy could plausibly transfer to other Nordhaus–Gaddum sums of spectral invariants, such as Laplacian or signless Laplacian eigenvalues, if an analogue of the structural lemma holds; the paper does not pursue this.
- The equality analysis suggests a stability statement: graphs whose spectral sum is within $\varepsilon$ of the maximum should be close, in edge-edit distance, to the complete split extremizers. No such stability bound is proved here.
- The explicit determinant computations in the exceptional case could be refined to extract a quantitative gap between subextremal graphs and the maximum, a testable extension of the same polynomial method.
Signed reviews
Editorial analysis
A structured set of objections, weighed in public.
Referee Report
Summary. The paper studies the Nordhaus-Gaddum problem for the spectral radius and claims to resolve Stevanović's 2007 conjecture: for every n, the maximum of ρ(G)+ρ(\bar G) over n-vertex graphs is attained by the complete split graph K_{⌊n/3⌋}∨N_{⌈2n/3⌉}, and, when n≡2 (mod 3), also by K_{⌈n/3⌉}∨N_{⌊2n/3⌋}. The proof uses Csikvári's reduction to staircase matrices, introduces parameters c,v,s and their complement counterparts, derives upper bounds φ(A) and φ(\bar A), then reduces to five residue-class cases and one exceptional case, which is handled by a Kronecker-sum matrix argument. The final section claims that every graph attaining the maximum is a complete split graph or its complement.
Significance. If correct, this is a complete proof of a conjecture that was previously known only for large n via analytic methods, and it is notable for being purely linear algebraic. The paper makes explicit parameter computations, gives equality cases for the row-sum bounds, and reduces the problem to a finite case analysis; these are concrete and checkable strengths. The main caveat is the dependence on the exact quantifier in Lemma 2.1, discussed below.
major comments (3)
- [§2, Lemma 2.1 and Remark 2.2] The proof of §7 begins 'By Lemma 2.1, A∈S*_s(n)' for an arbitrary graph with ρ(A)+ρ(\bar A)≥ρ0. This requires the universal reading of Lemma 2.1: every extremal graph admits a staircase ordering. The manuscript's own Remark 2.2 states that Csikvári [5] showed the maximum is achieved by a graph with a staircase ordering and then asserts, without proof, that the maximum is attained only by such graphs. If only the existential reading holds, the argument in §§3–7 does not classify every extremal graph, and the final conclusion that G or its complement is complete split is not justified. The conjecture itself can still be recovered by applying the proof to an extremal representative in S*_s, but the quantifier in Lemma 2.1 and the wording of Remark 2.2 must be corrected or the universal statement proved.
- [§3, Proposition 3.2] Proposition 3.2 is stated as ρ(A)<ρ(A1), but the proof shows only φ(A)<φ(A1) via (3.2). Because ρ(A)≤φ(A) and ρ(A1)≤φ(A1), the strict inequality for ρ does not follow from the displayed argument. The subsequent applications (after Figure 1 and in Lemma 3.3) use the φ comparison, so the proposition should be restated as φ(A)<φ(A1); if ρ(A)<ρ(A1) is intended, additional justification is needed.
- [§6, Lemma 6.3 and §7] The derivation of (6.4) and the later use of the equality case of (5.1) in Proposition 6.5 silently assume equality in Lemma 5.1. Lemma 5.1 states only a sufficient condition for equality, and the matrices obtained after Lemma 3.4 satisfy v=n−\bar c rather than v=n−\bar c−1. The equality is true when c+\bar c≥n because then a_{c+1,n−\bar c}=1 and row c+1 has exactly n−\bar c ones, but this justification is omitted. Please add it explicitly, since Lemma 6.3 is the basis for the monotonicity of g(x) in Proposition 6.4.
minor comments (3)
- [Throughout] Several typos should be corrected: 'suck' → 'such' in the proof of Lemma 2.9, 'shell' → 'shall' in the proof of Proposition 6.1, 'Morover' → 'Moreover' in Lemma 3.5, 'Disctrete' → 'Discrete' in reference [2], and 'Cambrigde' → 'Cambridge' in reference [9].
- [§3, Lemma 3.5] The proof of Lemma 3.5 is much less detailed than that of Lemma 3.4; please specify the row and column moves used in the construction of A2 and the termination condition for the iterative process.
- [§3, after (3.3)] The informal description of reading the complement parameters 'leftward from the a_{6,6} position' is hard to follow; a more systematic explanation of how to compute \bar c, \bar v, \bar s from A would improve readability.
Circularity Check
No significant circularity: the upper-bound chain is derived from independent row-sum theorems, and the extremal equality is forced by their equality cases rather than by fitting the conjecture.
full rationale
The paper does not assume Conjecture 1.1. Section 3 defines the upper bound phi(A) from Theorem 2.3 (Liu-Weng and Duan-Zhou), and Section 5 bounds c+c-bar by a counting inequality; both are independent of the extremal value. The equality analysis in Lemma 4.1 uses the equality condition of Theorem 2.3 to characterize when rho(A)+rho(A-bar)=phi(A)+phi(A-bar), yielding complete split graphs. Section 7 combines these upper bounds, not any fitted parameter, so no prediction is forced by construction. The authors' own Theorem 2.5 (Cheng-Weng [4]) is used only in the final (3k+2,2k+1,2k+1) case as a published comparison theorem with stated hypotheses; it is not a self-citation chain replacing the proof, and it does not assume the target result. The one genuine caveat is Remark 2.2: the paper asserts, without proof, that Csikvari's argument shows the S*_s condition is 'essential' and that the maximum 'is attained only by such graphs,' whereas the quoted Lemma 2.1 as stated gives existence of an ordering for each extremal graph. If only the weaker existential reading is available, Section 7's opening 'By Lemma 2.1, A in S*_s(n)' for an arbitrary graph G is unsupported, and the classification of every extremal graph would not follow. That is a verification gap and correctness risk about the cited lemma, not a circular derivation: the theorem's conclusion is not equivalent to any of the paper's inputs, and no equation or fitted parameter is renamed as the answer.
Assumptions & free parameters
assumptions (4)
- domain assumption Lemma 2.1 (Csikvári [5]): an extremal graph has a vertex ordering whose adjacency matrix lies in S*_s(n).
- standard math Theorem 2.3: ρ(A) ≤ φ_ℓ(A) for (0,1)-matrices with sorted row sums, from Liu-Weng [10] and Duan-Zhou [6].
- standard math Theorem 2.5: rooted-matrix bound of Cheng-Weng [4].
- standard math Standard Perron-Frobenius and equitable partition lemmas (Lemmas 2.6, 2.7).
Cite this review
Pith. "Pith review of Nordhaus-Gaddum inequality for the spectral radius of a graph of order $n$." pith.science (2026). https://pith.science/paper/CQC4JBPB
@misc{pith2026250611401,
author = {Pith},
title = {Pith review of: Nordhaus-Gaddum inequality for the spectral radius of a graph of order $n$},
year = {2026},
howpublished = {\url{https://pith.science/paper/CQC4JBPB}},
note = {Machine review of arXiv:2506.11401}
}
abstract
We determine the extremal graph $G$ of order $n$ that maximizes the sum of the spectral radii of $G$ and its complement. This resolves a conjecture posed by Stevanovi\'{c} in 2007.
Figures
Forward citations
Cited by 1 Pith paper
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Generalized Nordhaus--Gaddum Inequalities for Eigenvalues
The asymptotic maximum of λ₁(G)+λ₂(complement of G) is exactly 8/7 per vertex, with new general bounds for all pairs and a short proof of Terpai's spectral-radius bound.
Reference graph
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Reviewed August 7, 2026 · model on record in the stance chip above.
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