Random 0/1-polytopes expand rapidly
Pith reviewed 2026-05-10 16:56 UTC · model grok-4.3
The pith
Random 0/1-polytopes have edge-expansion Θ(n) for dense sampling and n^Θ(log log n) for sparser sampling.
A machine-rendered reading of the paper's core claim, the machinery that carries it, and where it could break.
Core claim
If V is formed by sampling each vertex of {0,1}^n independently with constant probability p, then with high probability the edge-expansion of the graph of the convex hull conv(V) is Θ(n) for p ∈ (1/2, 1), and n^Θ(log log n) for p ∈ (0, 1/2).
What carries the argument
The edge-expansion of the 1-skeleton graph of conv(V), defined as the minimum over nonempty proper subsets S of the number of edges leaving S divided by the size of the smaller of S and its complement.
Load-bearing premise
Vertices are included independently with a probability p that stays fixed as dimension n grows.
What would settle it
An explicit construction or numerical check for sufficiently large n and p=0.6 that exhibits a cut whose crossing-edge density is o(n).
read the original abstract
A 0/1-polytope is the convex hull of a subset $V\subseteq \{0,1\}^n$. A celebrated conjecture of Mihail and Vazirani asserts that the graph of every 0/1-polytope has edge-expansion at least 1. In this paper, we show that typical 0/1-polytopes have significantly stronger expansion. Specifically, if $V$ is formed by sampling each vertex of $\{0,1\}^n$ independently with constant probability $p$, then with high probability the edge-expansion is $\Theta(n)$ for $p \in (1/2, 1)$, and $n^{\Theta(\log \log n)}$ for $p \in (0, 1/2)$. This improves the previously best known bound $\Omega(1)$ due to Ferber, Krivelevich, Sales and Samotij.
Editorial analysis
A structured set of objections, weighed in public.
Referee Report
Summary. The manuscript claims that if V is a random subset of the vertices of the n-cube obtained by including each point independently with constant probability p, then with high probability the edge-expansion of the 1-skeleton of conv(V) is Θ(n) for p ∈ (1/2,1) and n^Θ(log log n) for p ∈ (0,1/2). This is presented as an improvement over the Ω(1) lower bound of Ferber et al. for the Mihail-Vazirani conjecture on 0/1-polytopes.
Significance. A correct proof of super-constant expansion for random 0/1-polytopes would be of interest in discrete geometry and expanders. The manuscript contains no machine-checked proofs or reproducible code. The central probabilistic claim is falsifiable in principle via sampling, but the stated result is internally inconsistent.
major comments (1)
- [Abstract] Abstract: The claimed high-probability expansion rates Θ(n) for p ∈ (1/2,1) and n^Θ(log log n) for p ∈ (0,1/2) cannot both hold. The model is invariant under the affine map x ↦ 1-x, a bijection on {0,1}^n. If V is sampled with parameter p then 1-V has the same distribution as a sample with parameter 1-p. This map induces a graph isomorphism between the 1-skeletons of conv(V) and conv(1-V), preserving edge-expansion exactly. Hence the distribution of the expansion is identical for p and 1-p, contradicting the distinct asymptotic regimes asserted.
Simulated Author's Rebuttal
We thank the referee for their thorough review of the manuscript. The main objection concerns an alleged internal inconsistency in the abstract regarding the expansion rates for p above and below 1/2, based on a symmetry argument. We explain below why this does not indicate an inconsistency in our claims.
read point-by-point responses
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Referee: [Abstract] Abstract: The claimed high-probability expansion rates Θ(n) for p ∈ (1/2,1) and n^Θ(log log n) for p ∈ (0,1/2) cannot both hold. The model is invariant under the affine map x ↦ 1-x, a bijection on {0,1}^n. If V is sampled with parameter p then 1-V has the same distribution as a sample with parameter 1-p. This map induces a graph isomorphism between the 1-skeletons of conv(V) and conv(1-V), preserving edge-expansion exactly. Hence the distribution of the expansion is identical for p and 1-p, contradicting the distinct asymptotic regimes asserted.
Authors: We appreciate the referee bringing this to our attention. However, the proposed symmetry does not map the parameter p to 1-p. Specifically, let φ(x) = 1 − x. For a random set V where each vertex of the hypercube is included independently with probability p, the probability that a fixed point y belongs to φ(V) is equal to the probability that φ(y) belongs to V, which is p. Therefore, φ(V) is distributed identically to V with the same p. While φ is indeed an automorphism of the hypercube preserving the edge structure, this symmetry preserves the sampling parameter and does not equate the distributions for p and 1-p. The distributions for p > 1/2 and p < 1/2 differ, for instance in the typical cardinality of V, allowing for potentially different expansion properties. We therefore see no contradiction with the stated results and do not plan to revise the abstract on this basis. revision: no
Circularity Check
No circularity; probabilistic expansion bounds derived independently from sampling model
full rationale
The paper's central claim is a direct probabilistic statement: random sampling of vertices from {0,1}^n with fixed p yields high-probability edge-expansion bounds that depend on whether p exceeds 1/2. No step reduces a derived quantity to a fitted parameter or self-referential definition by construction, nor does any load-bearing premise rest on a self-citation chain. The derivation relies on standard probabilistic method and graph-expansion arguments applied to the 1-skeleton, remaining self-contained against external benchmarks. The noted symmetry under coordinate complementation (p vs 1-p) raises a potential correctness issue but does not create circularity in the logical chain.
Axiom & Free-Parameter Ledger
axioms (2)
- standard math Edge-expansion is defined as the minimum over nonempty proper subsets S of the number of edges leaving S divided by |S|.
- domain assumption A 0/1-polytope is the convex hull of a subset of the vertices of the unit hypercube.
Reference graph
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discussion (0)
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