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arxiv: 2605.03181 · v1 · submitted 2026-05-04 · 🧮 math.CO · math.NT

On the largest Sidon subset in a finite subset of mathbb{R}^N

Pith reviewed 2026-05-07 02:26 UTC · model grok-4.3

classification 🧮 math.CO math.NT
keywords sidonsqrtmathbbsubsetboundfinitefracintegers
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The pith

Any n-element set of integers or points in R^N contains a Sidon subset of cardinality at least (1/(3 sqrt(3)) + o(1)) sqrt(n).

A machine-rendered reading of the paper's core claim, the machinery that carries it, and where it could break.

A Sidon set is one in which all pairwise sums a+b with a ≤ b are distinct. The quantity H(n) is the smallest, over all n-element integer sets, of the size of the largest Sidon subset inside it. The authors obtain H(n) ≥ (1/(3 sqrt(3)) + o(1)) sqrt(n) by first compressing an arbitrary integer set into a large subset that admits an injective Freiman 2-homomorphism into a cyclic group, then invoking Singer's known partition of Z/(q^2+q+1)Z into Sidon sets. The same numerical constant is shown to hold for point sets in Euclidean space of any dimension by a projection-plus-Dirichlet-approximation argument that preserves the Sidon equation. The method also yields an analogous lower bound of order sqrt(g n) for B_2[g] sets.

Core claim

H(n) ≥ (1/(3 sqrt(3)) + o(1)) sqrt(n) ≳ 0.19 sqrt(n), and the same lower bound holds uniformly for every finite subset of R^N.

Load-bearing premise

The compression lemma produces a subset large enough that, after the Singer covering is applied, the resulting constant remains strictly larger than Abbott's previous bound.

read the original abstract

We obtain a new lower bound on the largest Sidon subset of an arbitrary finite set of integers. If $H(n)$ denotes the minimum, over all $n$-element subsets of $\mathbb Z$, of the largest Sidon subset they contain, we prove that $H(n) \geqslant \left(\frac{1}{3\sqrt 3}+o(1)\right)\sqrt n \gtrsim 0.19\sqrt n$. This improves a lower bound of Abbott related to a conjecture of Erd\H{o}s on Sidon subsets of arbitrary sets of integers. The main ingredient is a compression lemma which produces, from any finite set of integers, a large subset admitting an injective Freiman $2$-morphism into a cyclic group. Combined with Singer's covering of $\mathbb Z/(q^2+q+1)\mathbb Z$ by Sidon sets, this yields the stated bound. We further extend the result to finite subsets of $\mathbb R^N$, uniformly in the dimension, by means of a projection argument and a Dirichlet approximation preserving Sidon's equation. As a consequence, every set of $n$ points in $\mathbb R^N$ contains a Sidon subset of cardinality at least $\left(\frac{1}{3\sqrt 3}+o(1)\right)\sqrt n$. We also discuss an adaptation to $B_2[g]$ sets, obtaining a lower bound of order $\frac{1}{3\sqrt 3}\sqrt{gn}$, and explain how the method can be adapted to other linear additive constraints.

Editorial analysis

A structured set of objections, weighed in public.

Desk editor's note, referee report, simulated authors' rebuttal, and a circularity audit. Tearing a paper down is the easy half of reading it; the pith above is the substance, this is the friction.

Axiom & Free-Parameter Ledger

0 free parameters · 1 axioms · 0 invented entities

The proof relies on the existence of Singer's Sidon covering of Z/(q^2+q+1)Z and on the existence of a sufficiently large Freiman 2-isomorphic subset; both are treated as standard background.

axioms (1)
  • standard math Singer's theorem supplies a covering of Z/(q^2+q+1)Z by Sidon sets of size q+1
    Invoked to obtain the numerical constant after compression.

pith-pipeline@v0.9.0 · 5564 in / 1160 out tokens · 30141 ms · 2026-05-07T02:26:28.508600+00:00 · methodology

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