REVIEW 5 major objections 5 minor 54 references
Weighted First-Order Model Counting over Ordered Domains
T0 review · 5 major / 5 minor · reviewed 2026-08-12 · deepseek-v4-flash
Pith's one-line read Weighted model counting over linearly ordered domains stays polynomial with one linear order and its successor relations, but becomes $\mathsf{\#P}_1$-hard with two independent linear orders — and stays tractable when only a second…
desk verdict Solid paper that pins down part of the WFOMC tractability frontier for ordered domains; the two-order hardness and hybrid tractability are genuinely new, but a few proofs need tightening. read the letter →
The pith
A machine-rendered reading of the paper's core claim, the machinery that carries it, and where it could break.
The reading
What carries the argument
A family of dynamic-programming algorithms built on the domain recursion rule. The domain is enlarged one element at a time in its linear order $1 \le 2 \le \cdots \le n$, and the algorithm's state is the cell configuration $\mathbf{k}$, where a cell (1-type) is a maximal consistent set of literals in a single variable. Pairwise interactions between cells are summarized by constants $r_{ij}$ computed from 2-tables, so each step multiplies the accumulated weighted count by cell weights and pairwise factors; because the sentence has no constants, all $n!$ orderings contribute equally, so the natural-order answer is multiplied by $n!$. Algorithm 2 additionally records the cell assignments of the last $k$ elements, exactly the information needed to fix the $k$-th successor relations, yielding time $O(p^{k+1} n^p)$ with $p$ the number of cells. Algorithm 3, for one linear order plus a second order's successor, tracks how the partial second order splits the prefix into segments (maximal $S$-chains) with head and tail cells, and applies five update rules — merge two segments, extend as head, extend as tail, or start a singleton — when the next element arrives. On the hardness side, the lever is a grid axiom that encodes a $\mathsf{\#P}_1$-hard tiling problem; Lemma 9's construction of Left/Right row markers plus three geometric observations forces any two linear orders to arrange the domain into exactly a square grid, with each grid corresponding to a unique model.
What would settle it
For small domains, compare Algorithm 2 against brute-force enumeration on a sentence with explicitly defined successor relations: any mismatch would break the bookkeeping behind Theorem 2. On the hardness side, a polynomial-time algorithm for the paper's 1-1-N-M counting tiling problem, or a domain-lifted counting procedure for the constructed two-linear-order sentence, would refute Theorem 3.
Extended reading notes
Core claim
The central assertion is that the tractability boundary for WFOMC over ordered domains sits strictly between one and two full linear orders. With a single linear order axiom, the two-variable fragment with counting quantifiers is domain-liftable: WFOMC is computed in time polynomial in the domain size, and the same holds for the extended axiom that also fixes the successor relations up to a constant order $k$. With two independent linear orders the situation flips: there are fixed two-variable sentences whose WFOMC is $\mathsf{\#P}_1$-hard, so counting is conditionally intractable even though satisfiability questions with one order are decidable. Between those poles sits a third result: one linear order together with the successor relation of a second, unknown order is again domain-liftable. Because a linear order can be encoded by an acyclicity constraint, the hardness transfers to two acyclic relations as well.
Load-bearing premise
The tractability theorems fix the sentence — and with it the number of cell types $p$ — and the successor bound $k$ as constants while the domain grows, and the hardness theorem assumes the tiling-to-Turing-machine encoding is exactly one-to-one so the two linear orders create no unintended models.
Editorial extensions
If this is right
- Exact lifted inference for hidden Markov models, time-series rules, and other sequence-structured C2 theories becomes polynomial in the domain size whenever one linear order is available.
- Grid-shaped models with constant width $k$ — including the 2-dimensional Ising model with constant interaction strength — become tractable through the $k$-th successor relations.
- Permutation-counting problems from combinatorics (grouped books, non-attacking kings, shuffled decks) reduce to polynomial-time WFOMC and run on domains of hundreds of elements, where propositional model counters fail at sizes in the teens.
- Any axiom that can encode a linear order, such as the acyclicity axiom, inherits the hardness: WFOMC with two acyclic relations is $\mathsf{\#P}_1$-hard, not merely two explicit linear orders.
- The successor relation of a second linear order can be exposed while keeping domain-liftability, so the intractability barrier is the second order's global structure, not its local adjacency.
Reading between the lines
- The parallel between the satisfiability frontier (one order decidable, two undecidable) and this counting frontier (one order domain-liftable, two $\mathsf{\#P}_1$-hard) suggests a transfer principle worth testing: undecidability of satisfiability over ordered domains may systematically predict WFOMC hardness, and decidability may predict liftability.
- The polynomial degrees are steep — the hybrid algorithm runs in time $O(n^{p^2+p+1})$ — so 'polynomial' does not mean 'fast': for ordered fragments the real lever is shrinking the number of cell types $p$, and on small domains even propositional counters can win. This predicts that cell-reduction and caching engineering will matter as much as the asymptotic results.
- The segment machinery appears to extend a further step inward from the hardness barrier: two successor relations of two unknown linear orders should remain tractable by counting segment configurations, a concrete next test the paper does not run.
Signed reviews
Editorial analysis
A structured set of objections, weighed in public.
Referee Report
Summary. The paper studies Weighted First-Order Model Counting (WFOMC) over domains equipped with linear order axioms. It claims four main results: (i) C2/FO2 with one linear order axiom is domain-liftable, via a dynamic program (Algorithm 1); (ii) FO2 with an extended linear order axiom including k-th successor relations is domain-liftable (Algorithm 2); (iii) FO2 with two linear order axioms is #P1-hard, proved by encoding a hard tiling problem through a grid axiom (Lemmas 7-9, Theorem 3); and (iv) FO2/C2 with one linear order and the successor relation of another linear order is domain-liftable (Algorithm 3, Theorem 4). The paper also reports experiments comparing the new algorithms with GANAK, d4, and RecursiveWFOMC, including matchings to OEIS sequences.
Significance. If the results are correct, they are significant: they extend the domain-liftability frontier to ordered domains, introduce a family of dynamic-programming algorithms with practical relevance to sequences, hidden Markov models, and grid-like structures, and they sharpen the known tractability/intractability boundary for WFOMC with order axioms. The algorithmic ideas are well connected to the existing literature on domain recursion, and the experimental validation against independent exact counters and OEIS sequences is a genuine strength. However, the hardness proof has a major uniformity gap, and the proofs of Algorithms 2 and 3 are substantially less complete than the statements require; these points must be fixed before the central claims can be accepted.
major comments (5)
- [§5.1–§5.3, Lemmas 8 and 9, Theorem 3] The hardness reduction is not to a fixed sentence. Lemma 8 constructs a sentence Ψ whose cardinality constraints |R1T3|=n and |R1T4|=m (Eq. (23)) depend on the inputs n,m of the 1-1-N-M tiling problem, while the domain size is (n+m+2)^2. Lemma 8 then invokes Lemma 2 to obtain an FO2 sentence without cardinality constraints, and Lemma 9 repeats this for the two-linear-order encoding. However, Lemma 2 as stated is a many-one reduction to one fixed FO2 sentence, whereas the cited result (Kuželka 2021) eliminates cardinality constraints by polynomial interpolation over several WFOMC evaluations with varying weights. Since the cardinality constants here vary with the input, the argument establishes hardness for a family of sentences parameterized by n,m, not the existence of a fixed FO2 sentence with two linear orders whose function n ↦ WFOMC(Ψ,n) is #P1-hard. Theorem 3 therefore needs a genuinely uniform fixed-sentence reduction, or the statement of the hardness notion must be revised.
- [§5.3, Lemma 9] The claimed equality WFOMC(Ψ∧G(H,V),n^2,w,w) = WFOMC(Ψ_l∧L(≤1)∧L(≤2),n^2,w,w) "for any weighting functions" is not correct as written. The left-hand sentence does not contain the auxiliary predicates First_i, Last_i, S_i, Left, Right, Top, Bottom, H, and V, while the right-hand side does; arbitrary weights on those predicates change the right-hand value. The proof must specify how the weighting functions are extended to the auxiliary predicates (e.g., all auxiliary weights set to 1) and state the resulting equality up to a constant factor. As written, the reduction is underspecified at a load-bearing point.
- [§4.1, Theorem 2] The proof of Algorithm 2 is not carried out. The displayed recursion for WMC(Φ_C2) is garbled: it uses r_il where only ˆr_il and ~r_il,s are defined, it contains a duplicated product over i∈[p], and it refers to Ω_m^s in a formula whose domain is of size m+1. In addition, Algorithm 2's pseudocode leaves t'_s undefined for s > min(i−1,k). Since Theorem 2 is a central positive result, the recurrence and the induction step need to be stated cleanly and proved in full.
- [§6.2, Theorem 4] The correctness proof for Algorithm 3 is only a sketch. The key claim that the pair-product contribution is determined by the state (k,ρ) is not stated as a lemma, the transition sums for merge1/merge2 with the η factors are not formally derived, and the proof that every configuration of segments counted by h_m(k,ρ) extends uniquely under the five update types is missing. The complexity bound also requires an argument counting the inner sums over a,b,c,d; they are polynomial in p, but the announced exponent O(n^{p^2+p+1}) is not justified as written. For an algorithm with this state-space complexity, a formal induction is necessary.
- [§5.1, Lemmas 6 and 7] The exact counting correspondence between accepting paths of the Turing machine and tilings is imported from a theorem usually stated for the NP-completeness of the bounded tiling problem. Since Lemma 8 converts the number of tilings to a WFOMC value by a factorial factor, any spurious tiling or missing boundary tile would invalidate the hardness argument. The paper should either provide a direct proof of the one-to-one correspondence or cite a source that states the counting version explicitly.
minor comments (5)
- [§2.3, Lemma 2] Lemma 2 is stated as a many-one reduction to a single FO2 sentence, but the cited work eliminates cardinality constraints by interpolation over multiple oracle calls. Please state the exact reduction type and whether the auxiliary sentence or weights may depend on the cardinality constants.
- [§4.1, Algorithm 2 and Theorem 2 proof] In the proof of Theorem 2, the same-cell formula uses set notation {a,b}∈Ω^s although Ω is defined as a set of ordered pairs; it should be (a,b)∈Ω^s.
- [§3.2, Lemma 4] Lemma 4 assumes a constant-free sentence, but this is not stated explicitly in the lemma; adding unary evidence breaks the symmetry argument, so the hypothesis should be made precise.
- [§5.3, Equations (24)–(33)] The observation that the ≤2-path decomposition has exactly n paths of length n depends on the domain size being exactly n^2 and on the boundary constraints; this step is plausible but should be expanded into a short formal argument rather than three informal observations.
- [§7, Experiments] The plots report runtimes for the propositional solvers excluding CNF construction; this is reasonable, but it should be stated once in the caption or text that the comparison is therefore only for the counting phase, not end-to-end grounding plus counting.
Circularity Check
No significant circularity: all main theorems are proved by explicit algorithms or reductions built on external primitives, not on the claimed conclusions.
full rationale
The paper's positive results (Theorems 1, 2, 4) are established by explicit dynamic-programming algorithms (Algorithms 1, 2, 3) built on the standard cell/2-table decomposition and domain-recursion rule, with correctness proved by induction over the domain size. The linear-order and successor axioms are treated as semantic constraints on distinguished relations; the algorithms compute weighted sums over all models satisfying those constraints, and no parameter is fitted to a target value that is later reported as a prediction. The negative result (Theorem 3) reduces WFOMC with two linear orders to a grid axiom, and then to a counting tiling problem whose #P1-hardness is imported from the external Lewis-Papadimitriou tiling encoding and the universal Turing machine of Beame et al. (2015); the authors' own Lemmas 7-9 supply the translation, not the hardness itself. Self-citations (e.g., Kuželka 2021 for eliminating counting quantifiers, Tóth and Kuželka 2024, Meng et al. 2024) are prior published results or baseline tools, disclosed and not used in place of proofs for the current claims. Experimental comparisons against independent solvers GANAK/d4 and OEIS sequences provide external checks. No equation is shown to equal its own input by construction, and no fitted quantity is renamed as a prediction. Hence the derivation chain is self-contained and non-circular.
Assumptions & free parameters
assumptions (5)
- standard math Lemma 2 (Kuzelka 2021): any C2 sentence with cardinality constraints and axioms can be reduced to FO2 WFOMC with an oracle.
- standard math FO2 sentences can be normalized to universal form forall x forall y psi(x,y) and decomposed into independent cells/2-tables (Beame et al. 2015; Van den Broeck et al. 2014).
- standard math The Lewis-Papadimitriou bounded tiling encoding (Lemma 6) maps accepting paths of a nondeterministic TM to tilings with a specified first row in a one-to-one way.
- domain assumption The linear order axiom is added semantically to the language: <= must be reflexive, antisymmetric, transitive, and total, and every total order is weighted symmetrically.
- domain assumption The fixed-sentence/data-complexity convention: sentence and weights are constant, only domain size n varies, so the number of cells p is constant.
Cite this review
Pith. "Pith review of Weighted First-Order Model Counting over Ordered Domains." pith.science (2026). https://pith.science/paper/IVDDLLL6
@misc{pith2026260810877,
author = {Pith},
title = {Pith review of: Weighted First-Order Model Counting over Ordered Domains},
year = {2026},
howpublished = {\url{https://pith.science/paper/IVDDLLL6}},
note = {Machine review of arXiv:2608.10877}
}
abstract
The Weighted First-Order Model Counting Problem (WFOMC) asks for the weighted sum of models of a first-order logical sentence over a domain. It is a fundamental problem in statistical relational learning, with applications extending to enumerative combinatorics and graph polynomials. Computing WFOMC for the three-variable fragment is $\mathsf{\#P}_1$-hard, whereas polynomial-time algorithms exist for the two-variable fragment and its extensions by cardinality constraints and counting quantifiers. In this work, we explore computing WFOMC in polynomial time over linearly ordered domains, enabling tractable reasoning across inference scenarios and combinatorial problems involving sequences. Because encoding a linear order in standard first-order logic requires three variables, negating our polynomial-time aspirations, we add a linear order axiom directly to the language. This forces one predicate to impose a total ordering on domain elements. We first prove that WFOMC with the linear order axiom can be solved in time polynomial in the domain size. We then extend this result to ordered domains with access to successor relations. While this holds when successors are explicitly defined via the linear order, we demonstrate an alternative implicit approach where successor relations are part of the axiom. This implicit method exhibits significantly better performance on all tested instances, sometimes providing exponential runtime improvements. Finally, we analyze scenarios with two distinct linear orders. We show that WFOMC over the two-variable fragment with two linear orders is $\mathsf{\#P}_1$-hard. However, we develop a polynomial-time algorithm for WFOMC with one linear order and a successor relation of another, pushing the intractability barrier further, yet still leaving the question of how close to a second full linear order one can get.
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Reviewed August 12, 2026 · model on record in the stance chip above.
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