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arxiv: 1610.09774 · v1 · pith:2P54YEFZnew · submitted 2016-10-31 · 🧮 math.CO · cs.CG· cs.DM

Lower Bounds on Davenport-Schinzel Sequences via Rectangular Zarankiewicz Matrices

classification 🧮 math.CO cs.CGcs.DM
keywords lambdawhendavenport-schinzelfunctionmatricesproblemsequencesall-1
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An order-$s$ Davenport-Schinzel sequence over an $n$-letter alphabet is one avoiding immediate repetitions and alternating subsequences with length $s+2$. The main problem is to determine the maximum length of such a sequence, as a function of $n$ and $s$. When $s$ is fixed this problem has been settled but when $s$ is a function of $n$, very little is known about the extremal function $\lambda(s,n)$ of such sequences. In this paper we give a new recursive construction of Davenport-Schinzel sequences that is based on dense 0-1 matrices avoiding large all-1 submatrices (aka Zarankiewicz's Problem.) In particular, we give a simple construction of $n^{2/t} \times n$ matrices containing $n^{1+1/t}$ 1s that avoid $t\times 2$ all-1 submatrices. Our lower bounds on $\lambda(s,n)$ exhibit three qualitatively different behaviors depending on the size of $s$ relative to $n$. When $s \le \log\log n$ we show that $\lambda(s,n)/n \ge 2^s$ grows exponentially with $s$. When $s = n^{o(1)}$ we show $\lambda(s,n)/n \ge (\frac{s}{2\log\log_s n})^{\log\log_s n}$ grows faster than any polynomial in $s$. Finally, when $s=\Omega(n^{1/t}(t-1)!)$, $\lambda(s,n) = \Omega(n^2 s/(t-1)!)$ matches the trivial upper bound $O(n^2s)$ asymptotically, whenever $t$ is constant.

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