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arxiv: 1705.04961 · v1 · pith:3EYWDRFFnew · submitted 2017-05-14 · 🧮 math.CA

Every locally finite Borel measure on mathbb{R} has conformal dimension zero

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keywords mathbbmeasureboreleveryconformaldimensionepsilonfinite
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A result of P. Tukia from 1989 says that Lebesgue measure on $\mathbb{R}$ has conformal dimension zero: for every $\epsilon > 0$, there is a Borel set $G \subset \mathbb{R}$ of full Lebesgue measure, and a quasisymmetric homeomorphism $f \colon \mathbb{R} \to \mathbb{R}$ such that $\dim_{\mathrm{H}} f(G) < \epsilon$. In this short note, I show that the same is true for every locally finite Borel measure on $\mathbb{R}$.

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