REVIEW 2 major objections 4 minor 25 references
Morrey's problem in $\mathbb{R}^{2 \times 4}$ and $\mathbb{R}^{3 \times 3}_\mathrm{sym}$
T0 review · 2 major / 4 minor · reviewed 2026-08-16 · deepseek-v4-flash
Pith's one-line read The paper constructs explicit rank-one convex integrands in $\mathbb{R}^{2\times4}$, $\mathbb{R}^{4\times4}_{\mathrm{sym}}$, and $\mathbb{R}^{3\times3}_{\mathrm{sym}}$ that fail quasiconvexity, giving the first Hessian counterexamples on…
desk verdict First explicit rank-one convex non-quasiconvex integrand in R^{2x4} and first Hessian counterexamples in symmetric spaces—genuinely new, but one unverified computer-algebra identity carries the whole construction. read the letter →
The pith
A machine-rendered reading of the paper's core claim, the machinery that carries it, and where it could break.
The reading
What carries the argument
The base object is the integrand $G(\xi,\eta)=\sqrt{\|\xi\|^{2}\|\eta\|^{2}-|\langle\xi,\eta\rangle|^{2}}$ on pairs of quaternionic vectors, identified with $\mathbb{R}^{8\times2}$; it is homogeneous, rank-one convex, and non-quasiconvex. The paper restricts it to purely imaginary quaternionic entries and transposes it to $\mathbb{R}^{2\times6}$. The central new device is a scalar potential $\psi_{\tau}$ on $\mathbb{T}^{4}$ with 12 cosine modes, chosen so that, with $\varphi_{\tau}=(\partial_{z_1}\psi_{\tau},-\partial_{y_1}\psi_{\tau})$, the expansion takes the form $G_{\mathrm{im}}^{T}(M+\varepsilon D\varphi_{\tau})^{2}=(4-\varepsilon^{2}S_{\tau})^{2}+\varepsilon^{4}E_{\tau}$. The $\varepsilon^{2}$ coefficient $S_{\tau}$ is a null Lagrangian—a function whose integral has zero average over the torus—while the $\varepsilon^{4}$ coefficient $E_{\tau}$ has torus average $96\tau(17\tau-2)$, verified symbolically; at $\tau=1/12$ this average is negative, so the fourth-order term drives the total integral down. For the symmetric $3\times3$ case, the machinery changes: four rank-one matrices $\xi_j\otimes\xi_j$ span a subspace where the integrand $-r_1r_2r_3r_4$ is convex along symmetric rank-one lines, and a four-mode trigonometric test map gives the negative variation.
What would settle it
Take the explicit 12-mode potential $\psi_{1/12}$ from (3.6), form $E_{1/12}$ from (3.4), and compute its average over $\mathbb{T}^4$ with an independent computer algebra system or high-precision quadrature; it must equal $-14/3$. Equivalently, evaluate $\int G_{\mathrm{im}}^{T}(M+\varepsilon D\varphi_{1/12})\,dx$ for several small $\varepsilon$ and check that the $\varepsilon^{4}$ coefficient approaches $-7/12$; any other value would break the strict inequality.
Extended reading notes
Core claim
The paper claims that the gap between rank-one convexity and quasiconvexity occurs in matrix spaces that were previously unresolved. Specifically, $F_{2,4}(A)=G_{\mathrm{im}}^{T}(M+\iota(A))$ on $\mathbb{R}^{2\times4}$ is rank-one convex but not quasiconvex at $0$: for the explicit 12-mode map $\tilde{\varphi}_{1/12}$ the averaged value of $F_{2,4}(\varepsilon D\tilde{\varphi}_{1/12})$ is strictly below $F_{2,4}(0)$ for all sufficiently small nonzero $\varepsilon$. The same construction, read through a scalar potential, gives $H$ on $\mathbb{R}^{4\times4}_{\mathrm{sym}}$ that is convex along every line $A+t(a\otimes a)$ but fails Hessian quasiconvexity, and a quartic polynomial on $\mathbb{R}^{3\times3}_{\mathrm{sym}}$ with a four-mode test map does the same in dimension three. Along the way, the paper shows that its starting eight-by-two quaternionic example contains the classical three-mode example as a leading-order slice.
Load-bearing premise
The argument stands on a long symbolic computation, reported but not reproduced in the text, that the torus average of $E_{\tau}$ is $96\tau(17\tau-2)$; at $\tau=1/12$ its negative sign is exactly what makes the averaged integrand decrease, so if that identity were wrong the counterexample would fail.
Editorial extensions
If this is right
- The explicit $\mathbb{R}^{2\times4}$ integrand shows the rank-one convex/quasiconvex gap does not require a very large number of columns; range dimension two is not by itself enough to force equivalence.
- The scalar-potential construction converts the gradient counterexample into Hessian counterexamples on symmetric $4\times4$ and $3\times3$ matrices, so for scalar second-order variational problems convexity along symmetric rank-one directions does not imply Hessian quasiconvexity.
- The sign of the fourth-order coefficient $96\tau(17\tau-2)$ is the deciding quantity; the choice $\tau=1/12$ is an explicit nondegenerate direction, and a computer-algebra verification is part of the argument.
- The construction does not settle the $2\times2$ or $2\times3$ cases; transposition is essential to the low-dimensional examples, and quasiconvexity is not invariant under transposition, so the same route cannot be applied directly to the square case.
Reading between the lines
- The 12-mode potential is a perturbation of a 9-mode profile that lies in the kernel of the fourth-order variation. A natural extension is to search for similar nondegenerate perturbations in $\mathbb{R}^{2\times3}$ or $\mathbb{R}^{2\times2}$, where lower-order cancellations might still be arranged while a higher-order term controls the sign.
- The descent pattern—restrict a high-dimensional quaternionic example to an algebraic subspace, transpose, then find a scalar potential—could be tested on other norm-based integrands; one concrete check is to enumerate Fourier modes satisfying the determinant-zero constraint $\det(k',k'')=0$ and look for negative fourth-order averages in lower dimensions.
- An independent proof of the 84-coefficient torus average could expose why the coefficient $17\tau-2$ has this particular form and may suggest optimal perturbations for other target spaces.
Signed reviews
Editorial analysis
A structured set of objections, weighed in public.
Referee Report
Summary. The manuscript constructs explicit rank-one convex, non-quasiconvex integrands in R^{2×4} and in the spaces of symmetric matrices R^{4×4}_sym and R^{3×3}_sym. The construction is based on Grabovsky's example in R^{8×2}; the authors identify a relationship with Šverák's example, then restrict and transpose to lower dimensions. For the R^{2×4} example, a twelve-mode map derived from a scalar potential produces a negative fourth-order variation whose sign is fixed by a computer-algebra identity. A modified Šverák-type construction yields the symmetric 3×3 example.
Significance. If the computations are correct, these are the first explicit counterexamples to 'rank-one convex implies quasiconvex' in R^{2×4} and in symmetric matrix spaces, resolving open cases in Morrey's problem. The examples are fully explicit and the key algebraic identity is backed by a public Mathematica notebook. The observed relation between Grabovsky's and Šverák's constructions is interesting in its own right and may guide further work on lower-dimensional and symmetric cases.
major comments (2)
- [Section 3, Eq. (3.7)] The proof of non-quasiconvexity of G^T_im, and hence of Corollaries 1.3 and 1.4, depends on the identity ∫ Eτ dx = 96τ(17τ−2). The text states that this is obtained with a computer algebra system and refers to a notebook, but does not reproduce the computation or even the structure of the Fourier-coefficient summation. Since the sign of this average is exactly what makes the variation negative, the central claim is not self-contained. Please either include a human-readable derivation, or move the notebook into the submission as supplementary material and add a short verification protocol, for example by listing the 84 scalar coefficients or by showing a symmetry reduction that makes the calculation transparent.
- [Section 4, Theorem 1.5] The extension from the subspace L to all of R^{3×3}_sym is dismissed with the phrase 'follows exactly as in [23]'. In the symmetric setting the relevant rank-one directions are matrices a⊗a, and the orthogonal projection of a⊗a onto L is not generally a rank-one matrix; for instance, with a=(1,2,3) the projection has full rank. The argument in [23] may still apply, but the authors should confirm that the same choice of α,λ,μ works in this setting, or give a reference to a symmetric-matrix version of the extension lemma. As written, this is a gap in the proof of Theorem 1.5.
minor comments (4)
- [Corollary 1.3 proof] The notation for the restricted map alternates between φ1/12 and φ~1/12 without consistency; please add tildes consistently so the reader can follow which domain is meant.
- [Section 2 heading] The heading 'Grabovsky's and Šveráks's examples' contains a typo; it should read 'Šverák's example'.
- [Section 3, Eq. (3.7)] It would be helpful to remark that the sign of 96τ(17τ−2) changes at τ=2/17 and that the choice τ=1/12 is one admissible value; a short sentence on the admissible range would aid reproducibility.
- [Introduction, AI disclosure] The AI disclosure is transparent, but it would fit more naturally in the acknowledgements than in the main text; this is purely a presentational suggestion.
Circularity Check
No significant circularity: the construction is explicit, the load-bearing prior art is external, and the one self-cited artifact is a reproducibility notebook rather than an imported theorem.
full rationale
The paper's central claim is a constructive counterexample, not a fitted prediction. Rank-one convexity of the new integrands follows by linear changes of variables from Grabovsky's externally published example [13] and from Sverak's example [23]; non-quasiconvexity is established by explicit Fourier test maps and the displayed inequality (3.9). The parameter tau=1/12 is not a fitted value: equation (3.7) gives the fourth-order average as 96*tau*(17*tau-2), which is negative for every tau in the open interval (0,2/17), so the choice is an open-condition selection, not an optimized fit. The main gap is that identity (3.7) is asserted as a computer-algebra computation and delegated to the authors' Mathematica notebook [1]; this is a verification and reproducibility issue, not circularity, because (3.7) is an independent arithmetic identity that does not assume the conclusion of non-quasiconvexity. The self-citation [1] is not used as an unverified theorem; it is an artifact supplied for checking. No uniqueness theorem from the authors is invoked to force a choice, and no known result is renamed as a new one. Thus there are no circular steps in the derivation chain.
Assumptions & free parameters
free parameters (2)
- tau =
1/12
- alpha, lambda, mu =
not specified, chosen as in Sverak [23]
assumptions (4)
- standard math Grabovsky's theorem: G:H^2 x H^2 -> [0,infinity) defined in (1.2) is rank-one convex and non-quasiconvex at I_2.
- standard math Sverak's extension argument [23]: the perturbed functional f(PZ)+alpha|PZ|^4+lambda|PZ|^2|QZ|^2+mu|QZ|^4 is rank-one convex for suitable positive constants.
- standard math Determinants are null Lagrangians, so the average of S_tau over T^6 vanishes as stated in (3.5).
- standard math Fourier orthogonality on the torus and Jensen's inequality.
Cite this review
Pith. "Pith review of Morrey's problem in $\mathbb{R}^{2 \times 4}$ and $\mathbb{R}^{3 \times 3}_\mathrm{sym}$." pith.science (2026). https://pith.science/paper/3MA2TODA
@misc{pith2026260812298,
author = {Pith},
title = {Pith review of: Morrey's problem in $\mathbbR^2 \times 4$ and $\mathbbR^3 \times 3_\mathrmsym$},
year = {2026},
howpublished = {\url{https://pith.science/paper/3MA2TODA}},
note = {Machine review of arXiv:2608.12298}
}
abstract
We find an explicit rank-one convex non-quasiconvex integrand in $\mathbb{R}^{2\times 4}$: to falsify the quasiconvexity inequality, we exhibit a map $\mathbb{T}^4\to \mathbb{R}^2$ with $12$ non-zero Fourier modes. In fact, this map is obtained from a scalar potential, so we also find a rank one convex integrand in $\mathbb{R}^{4\times 4}_\text{sym}$ which is not quasiconvex. These examples are obtained by transpositions and restrictions of Grabovsky's example of a rank-one convex, non-quasiconvex integrand in $\mathbb{R}^{8 \times 2}.$ We also modify \v{S}ver\'{a}k's example to construct a rank-one convex non-quasiconvex integrand in $\mathbb{R}^{3\times 3}_\text{sym}$.
Reference graph
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Reviewed August 16, 2026 · model on record in the stance chip above.
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