A tournament of order 24 with two disjoint TEQ-retentive sets
classification
💻 cs.MA
math.CO
keywords
alternativesconjecturecounterexampleschwartzbrandtconcretedisjointdisproved
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Brandt et al. (2013) have recently disproved a conjecture by Schwartz (1990) by non-constructively showing the existence of a counterexample with about 10^136 alternatives. We provide a concrete counterexample for Schwartz's conjecture with only 24 alternatives.
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