pith. sign in

arxiv: 1809.06041 · v1 · pith:4J5O4FC6new · submitted 2018-09-17 · 💻 cs.CC · cs.DS

Equivalence between pathbreadth and strong pathbreadth

classification 💻 cs.CC cs.DS
keywords pathbreadthdecompositiondenotedempheveryexistsgraphneighbourhood
0
0 comments X
read the original abstract

We say that a given graph $G = (V, E)$ has \emph{pathbreadth} at most $\rho$, denoted $\pb(G) \leq \rho$, if there exists a Roberston and Seymour's path decomposition where every bag is contained in the $\rho$-neighbourhood of some vertex. Similarly, we say that $G$ has \emph{strong pathbreadth} at most $\rho$, denoted $\spb(G) \leq \rho$, if there exists a Roberston and Seymour's path decomposition where every bag is the complete $\rho$-neighbourhood of some vertex. It is straightforward that $\pb(G) \leq \spb(G)$ for any graph $G$. Inspired from a close conjecture in [Leitert and Dragan, COCOA'16], we prove in this note that $\spb(G) \leq 4 \cdot \pb(G)$.

This paper has not been read by Pith yet.

discussion (0)

Sign in with ORCID, Apple, or X to comment. Anyone can read and Pith papers without signing in.