Nash problem for surfaces
classification
🧮 math.AG
math.CV
keywords
nashalgebraicalgebraicallybijectivecharacteristiccloseddefinedfield
read the original abstract
We prove that Nash mapping is bijective for any algebraic surface defined over an algebraically closed field of characteristic 0.
This paper has not been read by Pith yet.
discussion (0)
Sign in with ORCID, Apple, or X to comment. Anyone can read and Pith papers without signing in.