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arxiv: 1607.01004 · v2 · pith:IJOXIKAKnew · submitted 2016-07-04 · 🧮 math.CO

On generalized hexagons of order (3, t) and (4, t) containing a subhexagon

classification 🧮 math.CO
keywords generalizedhexagonsordercontainingequalfullhexagonsemi-finite
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We prove that there are no semi-finite generalized hexagons with $q + 1$ points on each line containing the known generalized hexagons of order $q$ as full subgeometries when $q$ is equal to $3$ or $4$, thus contributing to the existence problem of semi-finite generalized polygons posed by Tits. The case when $q$ is equal to $2$ was treated by us in an earlier work, for which we give an alternate proof. For the split Cayley hexagon of order $4$ we obtain the stronger result that it cannot be contained as a proper full subgeometry in any generalized hexagon.

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