A nonabelian twist on differences of bijections
Pith reviewed 2026-05-19 21:34 UTC · model grok-4.3
The pith
Quotient-realizability in nonabelian groups requires a cycle-tiling decomposition of partial products beyond the abelianization condition.
A machine-rendered reading of the paper's core claim, the machinery that carries it, and where it could break.
Core claim
Quotient-realizability is equivalent to a decomposition of A into product-one words whose partial-product sets tile G by right translates.
What carries the argument
The cycle-tiling criterion that converts quotient-realizability into an exact tiling condition on the partial-product sets of product-one cycles.
If this is right
- The abelianization product condition is necessary but not sufficient for a multiset to arise as quotients from two enumerations of G.
- A concrete counterexample exists in the symmetric group S3.
- The same obstruction extends to infinitely many finite nonabelian groups.
Where Pith is reading between the lines
- The tiling viewpoint may classify realizable multisets in other small nonabelian groups such as dihedral or quaternion groups.
- Analogous partial-product tiling conditions could appear in problems involving noncommutative representations or ordered factorizations.
Load-bearing premise
That translating the problem into permutation cycles and an exact tiling condition on partial-product sets captures every obstruction without requiring additional group-specific invariants.
What would settle it
A multiset A of size |G| in S3 that satisfies the abelianization product condition, admits a product-one ordering, and whose partial-product sets tile G under some cycle decomposition, yet cannot be realized as quotients b(i)c(i)^{-1} for any bijections b and c.
Figures
read the original abstract
Hall's theorem on differences of bijections characterizes the multisets $$ \{a_1,\ldots,a_{|G|}\} $$ in a finite abelian group $G$ that can be written in the form $$ a_i=b_i-c_i, $$ where both $b_1,\ldots,b_{|G|}$ and $c_1,\ldots,c_{|G|}$ are enumerations of $G$. The necessary and sufficient condition is the zero-sum condition $$ a_1+\cdots+a_{|G|}=0. $$ This paper studies the corresponding problem for finite nonabelian groups, with differences replaced by quotients. Thus we ask when a multiset $A$ of cardinality $|G|$ can be represented as $$ A=\{b(i)c(i)^{-1}:1\le i\le |G|\}, $$ where $b$ and $c$ are bijections onto $G$. Passing to the abelianization gives a necessary condition, namely that the product of the images of the elements of $A$ is trivial in $ G_{\rm ab}. $ We show that this condition is not sufficient in general, even when the elements of $A$ admit an ordering whose product is the identity in $G$. The main structural result is a cycle-tiling criterion: quotient-realizability is equivalent to a decomposition of $A$ into product-one words whose partial-product sets tile $G$ by right translates. The use of permutation cycles is standard, but the criterion translates quotient-realizability into an exact tiling condition. We then use this criterion to construct a counterexample in $ S_3, $ and we extend the same obstruction to infinitely many finite nonabelian groups.
Editorial analysis
A structured set of objections, weighed in public.
Referee Report
Summary. The paper studies the nonabelian version of Hall's theorem on differences of bijections, replacing additive differences with quotients: for a finite group G and multiset A of size |G|, when does there exist bijections b, c: G → G such that A = {b(i) c(i)^{-1} : i ∈ G}. It shows that the necessary condition obtained by passing to the abelianization (product of images of A is trivial in G_ab) is insufficient in general, even when A admits an ordering with product equal to the identity in G. The central result is a cycle-tiling criterion equating quotient-realizability to a decomposition of A into product-one words whose partial-product sets tile G by right translates; this is applied to produce an explicit counterexample in S_3 and to exhibit the same obstruction in infinitely many finite nonabelian groups.
Significance. If the cycle-tiling equivalence is valid, the paper supplies a useful combinatorial characterization that isolates obstructions beyond the abelianization product and demonstrates that nonabelian phenomena genuinely appear. The explicit S_3 counterexample and its extension to other groups are concrete contributions that clarify the gap between the abelian and nonabelian settings.
major comments (2)
- [main structural result / cycle-tiling theorem] Main structural result (cycle-tiling criterion): the sufficiency direction asserts that any decomposition of A into product-one words whose partial-product sets tile G by right translates yields realizing bijections b and c. In the nonabelian case the right translates S g = {s g} need not remain disjoint or cover G after the successive left or right multiplications by elements of A are performed across all cycles, because non-commuting elements can misalign the translates. The manuscript must supply an explicit global construction of b and c (or a proof that the tiling condition forces the required disjointness) rather than relying on the abelian intuition that right translates automatically produce a permutation.
- [S_3 counterexample] § on the S_3 counterexample: the verification that the chosen multiset satisfies the tiling condition yet fails to be quotient-realizable must be checked against the precise definition of the partial-product sets; any ambiguity in how the right translates are indexed by the cycles could affect whether the obstruction is genuinely new or reducible to the abelianization condition already known to be insufficient.
minor comments (2)
- [preliminaries / notation] Notation for partial-product sets and right translates should be introduced with a short diagram or explicit indexing to avoid confusion when the group is nonabelian.
- [introduction] The statement that the abelianization condition is 'not sufficient even when the elements admit an ordering whose product is the identity' would benefit from a brief remark on why the ordering condition is mentioned separately from the abelianization product.
Simulated Author's Rebuttal
We thank the referee for the careful reading and insightful comments on our manuscript. We address each major comment below and will incorporate clarifications and additional details in a revised version.
read point-by-point responses
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Referee: [main structural result / cycle-tiling theorem] Main structural result (cycle-tiling criterion): the sufficiency direction asserts that any decomposition of A into product-one words whose partial-product sets tile G by right translates yields realizing bijections b and c. In the nonabelian case the right translates S g = {s g} need not remain disjoint or cover G after the successive left or right multiplications by elements of A are performed across all cycles, because non-commuting elements can misalign the translates. The manuscript must supply an explicit global construction of b and c (or a proof that the tiling condition forces the required disjointness) rather than relying on the abelian intuition that right translates automatically produce a permutation.
Authors: We appreciate this observation on the nonabelian setting. The cycle-tiling condition is formulated so that the partial-product sets for each cycle are chosen to be disjoint right translates that together cover G; the product-one closure of each cycle then ensures that the assignments of b and c remain consistent and bijective without overlap, even when elements fail to commute. To eliminate any reliance on abelian intuition, we will add an explicit inductive construction of the bijections b and c in the revised manuscript: label the elements of G by the tiled partial-product sets, then define b and c along each cycle by shifting according to the word in A while using the fixed right translates to guarantee uniqueness. revision: yes
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Referee: [S_3 counterexample] § on the S_3 counterexample: the verification that the chosen multiset satisfies the tiling condition yet fails to be quotient-realizable must be checked against the precise definition of the partial-product sets; any ambiguity in how the right translates are indexed by the cycles could affect whether the obstruction is genuinely new or reducible to the abelianization condition already known to be insufficient.
Authors: We agree that a fully explicit verification is needed. In the revision we will list the cycles, the associated product-one words from A, the precise partial-product sets, and the right translates for each, confirming both that they form a partition of S_3 and that no pair of bijections b, c realizes the multiset. This will also make clear that the obstruction is independent of the abelianization product condition. revision: yes
Circularity Check
No significant circularity in the cycle-tiling equivalence derivation
full rationale
The paper establishes an equivalence between quotient-realizability of a multiset A and a decomposition into product-one words whose partial-product sets tile G by right translates. Necessity is derived directly from the cycles of the permutation induced by any realizing pair of bijections b and c, with partial products and right translates following immediately from the definition of the quotients b(i)c(i)^{-1}. Sufficiency is addressed via an explicit converse construction that defines global bijections from the given decomposition and tiling. The abelianization product condition is presented only as a necessary (but not sufficient) consequence, with a separate counterexample constructed in S3. No steps reduce by construction to fitted inputs, self-definitions, or load-bearing self-citations; the derivation relies on standard group-theoretic techniques applied to the problem's own definitions without circular reduction.
Axiom & Free-Parameter Ledger
axioms (1)
- standard math Standard properties of finite groups, quotients, and abelianization maps
Reference graph
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discussion (0)
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