Longest common subsequences in sets of words
classification
🧮 math.CO
keywords
commonlengthwordsalphabetdependingexistsfracgiven
read the original abstract
Given a set of $t$ words of length $n$ over a $k$-letter alphabet, it is proved that there exists a common subsequence among two of them of length at least $\frac{n}{k}+cn^{1-1/(t-k-2)}$, for some $c>0$ depending on $k$ and $t$. This is sharp up to the value of $c$.
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