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Maker-Breaker is solved in polynomial time on hypergraphs of rank 3

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arxiv 2209.12819 v4 pith:MZGN5PPN submitted 2022-09-26 cs.DM math.CO

classification cs.DMmath.CO
keywords hypergraphsrankmakermaker-breakeroutcomestructuralverticesalgorithm
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abstract

In the Maker-Breaker positional game, Maker and Breaker take turns picking vertices of a hypergraph $H$, and Maker wins if and only if she possesses all the vertices of some edge of $H$. Deciding the outcome (i.e., which player has a winning strategy) is a PSPACE-complete problem even when restricted to 4-uniform hypergraphs [Galliot, 2025]. As for hypergraphs of rank 3, the linear subcase (i.e., any two distinct edges intersect on at most one vertex) has been solved by obtaining a structural characterization of the outcome and a polynomial-time algorithm to decide it [Kutz, 2005]. A conjecture [Rahman and Watson, 2020] implies that the same results can be obtained for general hypergraphs of rank 3, which we confirm in this paper. We provide a structural characterization of the outcome and a description of both players' optimal strategies, all based on intersections of some key subhypergraph collections. From this, we derive a polynomial-time algorithm, thus closing the complexity gap for Maker-Breaker games relative to the size of the edges. Another corollary of our structural result is that, if Maker has a winning strategy on a hypergraph of rank 3, then she can ensure to win the game within a number of rounds that is logarithmic in the number of vertices.

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Cited by 2 Pith papers

Reviewed papers in the Pith corpus that reference this work. Sorted by Pith novelty score. Full citation record

  1. Maker-Maker games of rank 4 are PSPACE-complete

    cs.DM 2025-04 accept novelty 8.0 of 10

    Maker-Maker games on hypergraphs of rank 4 are PSPACE-complete, via a reduction from 3-QBF through achievement games with disjoint red edges.

  2. Faster Algorithms for Deciding the Unbiased Maker-Breaker Triangle Game on General Graphs

    cs.CC 2026-07 conditional novelty 7.0 of 10

    The winner of the unbiased triangle game can be decided in O(n^7) time on general graphs, O(n^{ω+1}) on connected K4-containing graphs, and O(n^3) when the edge-triangle incidence graph is a cactus.

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