REVIEW 1 major objections 5 minor 1 cited by
New results similar to Lagrange's four-square theorem
T0 review · 1 major / 5 minor · reviewed 2026-08-12 · deepseek-v4-flash
Pith's one-line read The paper proves that every sufficiently large integer is a sum of four values of a single quadratic polynomial from a broad family, generalizing the four-square theorem.
desk verdict Broadens the Lagrange-style four-square family to a two-parameter quadratic sequence, and the central theorems hold up; Theorem 1.5 has a localized but fixable congruence slip. read the letter →
The pith
A machine-rendered reading of the paper's core claim, the machinery that carries it, and where it could break.
The reading
What carries the argument
The machinery is a reduction to a four-square-with-prescribed-sum lemma. If $c$ and $d$ have the same parity, $4\nmid c$, and $d^2/4<c<(d^2+2d+4)/3$, then $c$ is a sum of four squares $w^2+x^2+y^2+z^2$ and $d$ is the sum $w+x+y+z$. The paper writes the target $n$ as $ac+bd$, chooses $d$ in a carefully positioned interval whose length exceeds the modulus step, and solves a congruence modulo $2a$ (or $4a$ or $6a$) so the resulting $c,d$ satisfy the lemma. The identity $n=a(w^2+x^2+y^2+z^2)+b(w+x+y+z)$ then becomes the desired sum $w(aw+b)/2+x(ax+b)/2+y(ay+b)/2+z(az+b)/2$. The weighted variants use analogous interval and congruence arguments with $5$ and $9$ divisors.
What would settle it
For $a=3$, $b=2$, and $n=187353$, the construction in the proof yields $d=585$ and $c\equiv6\pmod9$, so the required $c\equiv3\pmod9$ fails; checking whether this $n$ is actually representable as $3w(3w+2)+x(3x+2)+y(3y+2)+z(3z+2)$ would show whether Theorem 1.5 is false or merely unproved for $b\equiv2\pmod3$.
Extended reading notes
Core claim
The central claim is that a single quadratic family $\{x(ax+b)/2 : x\in\mathbb{N}\}$, for coprime $a,b$ with the right parity, represents all sufficiently large integers as a sum of four elements. The flagship case is the second pentagonal numbers: with $(a,b)=(5,1)$, every integer $n>1$ can be written as $w(5w+1)/2+x(5x+1)/2+y(5y+1)/2+z(5z+1)/2$ with $w,x,y,z\in\mathbb{Z}$. The same method yields weighted variants, including sums where one summand carries a factor $2$ or where the first coefficient is $3$, each with explicit thresholds and short exception lists. The theorems are effective: they give bounds rather than only a statement of eventual representability.
Load-bearing premise
The proof of the coefficient-three theorem assumes a divisibility identity that only holds for $b=1$; for many allowed values of $b$ the constructed numbers violate the condition the final lemma needs, so the claim is not established for those parameters.
Editorial extensions
If this is right
- For $(a,b)=(5,1)$, every integer $n>1$ is a sum of four generalized second pentagonal numbers, settling the second-pentagonal analogue of the four-square theorem.
- For each admissible $(a,b)$, the explicit threshold in Theorem 1.1 turns the asymptotic statement into a finite verification problem; the corollaries show such verifications produce clean exception lists such as $\{1,3,5,10,12,20,25,27,38,53,65,153,165\}$.
- The weighted theorems show that replacing one coefficient by $2$ or $3$ preserves four-term universality over the integers for all large targets, matching the earlier coefficient-$1$ results.
- In the even-$b$ case, Theorem 1.3 implies the same family is an asymptotic base of order five, because one of $n$ or $n-(a+b)$ is never divisible by $4$.
Reading between the lines
- The explicit bounds are likely far from sharp: the interval-length method typically pays large constants, and the paper's own numerical corollaries suggest the true thresholds are much smaller for small $a,b$.
- The congruence difficulty in the coefficient-$3$ theorem appears repairable by a different residue choice; if repaired, the coefficient-$3$ statement would likely hold for all odd coprime pairs, matching the exception lists the paper derives.
- The same reduction template could apply to any quadratic whose values pair with four-square-sum data through $n=ac+bd$, suggesting that the class of four-term asymptotic bases of order four may be much broader than the families listed in the theorems.
Editorial analysis
A structured set of objections, weighed in public.
Referee Report
Summary. The paper proves several effective asymptotic-basis statements for families of quadratic polynomials. Theorem 1.1 shows that for a>0, b>-a, gcd(a,b)=1, and 2∤ab, the set {x(ax+b)/2 : x∈N} is an asymptotic base of order four, with an explicit bound in (1.1); Theorems 1.2 and 1.3 give analogous statements in the even-a and even-b cases for the unhalved polynomials; Theorem 1.4 handles a coefficient 2 on one variable with gcd(a,5b)=1; and Theorem 1.5 treats a coefficient 3 under a parity hypothesis. The paper derives concrete corollaries, including the headline statement that every integer n>1 is a sum of four generalized second pentagonal numbers, and several exact descriptions of representable sets after finite computer checks. The proofs are elementary, based on variants of Cauchy's four-square lemma and interval arguments.
Significance. If the proofs are completed, the paper makes a meaningful contribution to additive number theory: it provides uniform effective four-square-type theorems for a two-parameter family of quadratic polynomials, extending classical results of Cauchy and Legendre as well as earlier work of Meng-Sun and Krachun-Sun. The bounds are explicit, the finite verifications in the corollaries are checkable, and Theorems 1.1-1.4 appear internally consistent. The principal weakness is the gap in Theorem 1.5, Case 2, which is load-bearing for that theorem and for Corollary 1.9. The gap is localized and appears repairable, so the central thesis of the paper remains plausible, but the manuscript as written is not fully correct.
major comments (1)
- [Section 4, Case 2 (proof of Theorem 1.5, p. 16)] The displayed computation of c is algebraically wrong for general b. From n=(b-a)d0+6aq and d=d0+6ar, the correct value is c=(n-bd)/a = 6q - d0 - 6br, not 6q - d0 - 6r. Therefore Lemma 4.1's requirement c≡3 (mod 9) is equivalent to br ≡ q + 1 + d0/3 (mod 3). The paper's choice r ≡ q + 1 + d0/3 (mod 3) works only when b≡1 (mod 3). For b≡2 (mod 3) the construction can produce a pair (c,d) with d≡0 (mod 3) but c not ≡ 3 (mod 9); a concrete instance is a=3, b=2, n=187353, where the construction gives d0=567, q=10440, r=1, d=585, and c=(187353-2·585)/3=62061≡6 (mod 9). Since this step is used for all parameters with 3|a, 3|n, and b≡2 (mod 3), Theorem 1.5 and Corollary 1.9 are not proved as written. The gap is local: choosing r with br≡q+1+d0/3 (mod 3) would restore the congruence, and d0+6ar remains in K because the interval length is >18a.
minor comments (5)
- [Theorem 1.5 statement] The hypothesis 'with ab or n even' should read 'with ab even or n even'; as printed the parity condition is ungrammatical and could be misread.
- [Corollary 1.6] The statement 'any integer /greaterorequalslant...' appears to have lost its variable; the bound should be explicitly attached to n.
- [Corollaries 1.1, 1.3, 1.5, 1.10, 1.11] Several corollaries rely on finite computer verifications described only as 'easy computations via a computer'; for reproducibility, the author should specify the verification range and, ideally, provide the checking code or the full list of small exceptional values.
- [Global presentation] The arXiv text contains numerous typographical artifacts, including 'RESUL TS' in the header, 'an y' in the abstract, and converted LaTeX symbols such as '/greaterorequalslant' and 'sufficiently'; these should be cleaned in the final version.
- [Section 5, Theorems 5.1 and 5.2] These theorems are asserted without proof, with the note that they follow from Lemma 5.1 and arguments similar to Section 2; since they are not used elsewhere, this is not blocking, but the author should either provide the proofs or clearly label the results as sketched.
Circularity Check
No significant circularity: target theorems are proved from independent Cauchy-type lemmas; the algebraic gap in Theorem 1.5 is a correctness issue, not a circular step.
full rationale
Theorems 1.1–1.5 are derived by reducing n = ac + bd to a four-square (or weighted four-square) representation of c with a prescribed digit sum d. The reduction is carried out in the paper: Theorem 2.1 chooses d in an interval I and then invokes Lemma 2.1; Theorem 1.4 reduces to Lemma 3.1; Theorem 1.5 reduces to Lemma 4.1. None of these lemmas states or assumes the target theorem. Lemma 2.1 is essentially Cauchy's classical lemma (Remark 2.1) with a parity variant from [4]; Lemma 4.1 is the analogous 3w² + x² + y² + z² lemma from [4]; Lemma 3.1 is a standalone characterization from [2]. These are parameter-free auxiliary results whose assumptions do not include the conclusion being proved, so citing them is independent evidence rather than circularity. The explicit bounds (1.1), (1.2), and (1.5) are derived from interval-length estimates, not fitted to the conclusions. No equation in the paper is equal to its target by construction, and no fitted value is renamed as a prediction. The reader's algebraic concern about Section 4, Case 2 (the congruence c ≡ 3 mod 9) is a proof-correctness gap for parameters with b ≡ 2 mod 3; it does not make the theorem an input to itself and therefore does not affect the circularity score.
Assumptions & free parameters
assumptions (4)
- standard math Lemma 2.1 (Cauchy's lemma variant): if c≡d (mod 2), 4∤c, 4c>d² and 3c<d²+2d+4, then c is a sum of four squares with sum d.
- domain assumption Lemma 3.1: every even n outside E={5^{2k+1}m: m≡±2 (mod 5)} is representable as x²+y²+z²+(x+y+z)²/2.
- domain assumption Lemma 4.1: under the stated congruence and inequalities, the system 3w²+x²+y²+z²=c and 3w+x+y+z=d is solvable.
- ad hoc to paper Finite computer verifications listed in corollaries are correct.
Cite this review
Pith. "Pith review of New results similar to Lagrange's four-square theorem." pith.science (2026). https://pith.science/paper/NJP6KT7D
@misc{pith2026241114308,
author = {Pith},
title = {Pith review of: New results similar to Lagrange's four-square theorem},
year = {2026},
howpublished = {\url{https://pith.science/paper/NJP6KT7D}},
note = {Machine review of arXiv:2411.14308}
}
abstract
In this paper we establish some new results similar to Lagrange's four-square theorem. For example, we prove that any integer $n>1$ can be written as $w(5w+1)/2+x(5x+1)/2+y(5y+1)/2+z(5z+1)/2$ with $w,x,y,z\in\mathbb Z$. Let $a$ and $b$ be integers with $a>0$, $b>-a$ and $\gcd(a,b)=1$. When $2\nmid ab$, we show that any sufficiently large integer can be written as $$\frac{w(aw+b)}2+\frac{x(ax+b)}2+\frac{y(ay+b)}2+\frac{z(az+b)}2$$ with $w,x,y,z$ nonnegative integers. When $2\mid a$ and $2\nmid b$, we prove that any sufficiently large integer can be written as $$w(aw+b)+x(ax+b)+y(ay+b)+z(az+b)$$ with $w,x,y,z$ nonnegative integers.
Forward citations
Cited by 1 Pith paper
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Universal quaternary mixed sums involving generalized 3-, 4-, 5- and 8-gonal numbers via products of Ramanujan's theta functions
The paper lists quaternary universal sums of generalized polygonal numbers, but its main proof lemma, Corollary 1.3, is false as stated.
Reference graph
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Reviewed August 12, 2026 · model on record in the stance chip above.
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