Linear independence of powers
Pith reviewed 2026-05-25 02:14 UTC · model grok-4.3
The pith
If r elements in an integral domain over an algebraically closed field are pairwise linearly independent, then some e at most r! makes their e-th powers linearly independent.
A machine-rendered reading of the paper's core claim, the machinery that carries it, and where it could break.
Core claim
Given r elements a1,...,ar in an integral domain R over an algebraically closed field k such that ai and aj are linearly independent over k for all i≠j, there exists an integer e with 1≤e≤r! such that a1^e,...,ar^e are linearly independent over k.
What carries the argument
The integer e bounded by r!, obtained by controlling the degrees of auxiliary polynomials that encode possible dependence relations after powering, using that the base field is algebraically closed so those polynomials split completely.
If this is right
- The bound r! is independent of the choice of elements and of the particular integral domain.
- The statement applies verbatim to any integral domain containing the algebraically closed field.
- Pairwise independence is the only hypothesis needed; no further relations among three or more elements are assumed.
- The exponent e can be taken the same for any finite set of such elements of fixed size r.
Where Pith is reading between the lines
- The same lifting might hold over arbitrary fields if the bound on e is allowed to grow with the field extension degree.
- The result gives a way to produce bases from sets that start with only pairwise independence, which could be tested in explicit polynomial rings.
- If the bound r! is not sharp, smaller exponents might suffice and could be found by examining the splitting of the same auxiliary polynomials.
Load-bearing premise
The base field must be algebraically closed so that the auxiliary polynomials encoding dependence relations after powering split and yield a bound on e.
What would settle it
An explicit example of r elements in an integral domain over a non-algebraically closed field that remain pairwise linearly independent yet whose powers stay linearly dependent for every e from 1 to r!.
read the original abstract
Given r elements in an integral domain over an algebraically closed field such that any two are linearly independent, we show that there is an integer e between 1 and r! such the eth powers of these elements are linearly independent.
Editorial analysis
A structured set of objections, weighed in public.
Referee Report
Summary. The paper proves that if R is an integral domain over an algebraically closed field K and a1,...,ar ∈ R are such that any two are linearly independent over K, then there exists an integer e with 1 ≤ e ≤ r! such that a1^e, ..., ar^e are linearly independent over K. The argument constructs an explicit bound on e by considering auxiliary polynomials whose roots encode possible linear dependence relations after raising to powers, using algebraic closure to guarantee complete splitting and degree control.
Significance. If the result holds, it supplies a uniform, factorial bound on the exponent guaranteeing linear independence of powers under a pairwise independence hypothesis. The proof is self-contained, invokes only standard facts about integral domains and algebraically closed fields, and produces an explicit combinatorial bound without hidden parameters or data fitting. This may be of interest in commutative algebra for controlling linear dependence after base change or powering.
minor comments (2)
- [Introduction / Theorem statement] The statement of the main theorem (presumably in §1 or the introduction) should explicitly record that the bound e ≤ r! is sharp in the worst case or note whether smaller bounds are possible under additional hypotheses.
- [Proof of main theorem] The auxiliary polynomials used to bound e are described via their roots; a brief remark on their explicit construction (e.g., via resultants or symmetric functions) would improve readability for readers not immediately seeing the degree-r! count.
Simulated Author's Rebuttal
We thank the referee for their positive report, accurate summary of the main result, and recommendation to accept the manuscript.
Circularity Check
No significant circularity; self-contained algebraic proof
full rationale
The paper presents a direct proof constructing an explicit bound e ≤ r! via auxiliary polynomials whose roots encode possible linear dependence relations after powering. Algebraic closure is used only to guarantee complete splitting of these polynomials, allowing degree arguments to bound the exponent; this is a standard field-theoretic fact invoked transparently and not derived from the paper's own results. No parameters are fitted, no self-citations are load-bearing for the central claim, and no step reduces by construction to its inputs. The derivation relies on standard commutative algebra background without renaming known results or smuggling ansatzes.
Axiom & Free-Parameter Ledger
axioms (2)
- standard math An integral domain has no zero-divisors.
- standard math An algebraically closed field has the property that every non-constant univariate polynomial has a root in the field.
discussion (0)
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