REVIEW 2 minor 13 references
Integrality of height-one formal groups
T0 review · 0 major / 2 minor · reviewed 2026-06-25 · grok-4.3
Pith's one-line read A one-dimensional formal group law over a finite extension of the p-adics has integral coefficients if and only if its multiplication-by-n endomorphisms do, when the group has height one.
desk verdict The paper proves an if-and-only-if for integrality of height-one formal groups over p-adics, with the converse relying on p-adic Hodge theory applied to the associated character. read the letter →
The pith
A machine-rendered reading of the paper's core claim, the machinery that carries it, and where it could break.
The reading
What carries the argument
The equivalence, for height-one groups, between integrality of the formal group law coefficients and integrality of all its [n]-endomorphisms, established via p-adic Hodge theory.
What would settle it
An explicit height-one formal group law over some finite extension of Q_p whose power-series coefficients lie outside the ring of integers while all its multiplication-by-n maps have integral coefficients, or the converse.
Extended reading notes
Core claim
Over a finite extension K of Q_p, a one-dimensional formal group law has integral coefficients if and only if its multiplication-by-n endomorphisms have integral coefficients for every integer n, provided the formal group has height one (that is, the multiplication-by-p map has Weierstrass degree p). The proof proceeds by applying p-adic Hodge theory to equate the two integrality statements.
Load-bearing premise
The formal group must have height one so that p-adic Hodge theory can be used to relate the integrality of the group law to the integrality of the endomorphisms.
Editorial extensions
If this is right
- Integrality of a height-one formal group law can be verified by checking only the endomorphisms rather than the entire group law.
- The criterion applies directly to formal groups attached to elliptic curves or Lubin-Tate extensions of height one over p-adic fields.
- Questions about integral models of formal groups can be rephrased as questions about integral endomorphisms.
Reading between the lines
- The equivalence might serve as a template for checking integrality in other p-adic settings where endomorphisms are easier to compute than the full law.
- It raises the question whether an analogous statement holds for formal groups of height greater than one, possibly after replacing p-adic Hodge theory with a different tool.
- Concrete examples such as the formal multiplicative group or the formal group of an ordinary elliptic curve could be used to test the sharpness of the height-one restriction.
Signed reviews
Editorial analysis
A structured set of objections, weighed in public.
Referee Report
Summary. The manuscript proves that for a one-dimensional formal group law over a finite extension K of Q_p, the group law has integral coefficients if and only if all its multiplication-by-n endomorphisms have integral coefficients, but only in the height-one case (i.e., when the multiplication-by-p map has Weierstrass degree p). One direction is purely algebraic; the converse applies p-adic Hodge theory to the one-dimensional Galois representation on the torsion points, using the height-one hypothesis to ensure the representation is a character to which the filtered phi-module correspondence applies directly.
Significance. If the result holds, it supplies a verifiable criterion for integrality of formal groups in terms of endomorphisms, which may be more accessible in computations. The explicit use of the height-one condition to reduce to a character and invoke p-adic Hodge theory without extra ramification hypotheses is a clear strength, as is the separation of the algebraic direction from the Hodge-theoretic one.
minor comments (2)
- [Abstract] Abstract: the parenthetical explanation of height one could be expanded by one sentence to note that this condition is used only for the converse direction.
- [Proof of converse] The manuscript would benefit from an explicit citation or short recall of the precise p-adic Hodge theorem (filtered phi-module correspondence for characters) invoked in the converse, even if standard.
Simulated Author's Rebuttal
We thank the referee for their positive assessment of the manuscript and for recommending acceptance. Their summary correctly identifies the if-and-only-if criterion in the height-one case and the separation between the algebraic direction and the p-adic Hodge theoretic direction.
Circularity Check
No significant circularity
full rationale
The paper proves an if-and-only-if equivalence between integrality of a one-dimensional formal group law and integrality of its [n] endomorphisms, restricted to the height-one case, via one algebraic direction and one direction that invokes p-adic Hodge theory on the associated Galois representation. No equations, fitted parameters, self-citations, or ansatzes are shown to reduce the claimed result to its own inputs by construction. The derivation is self-contained against external benchmarks (algebraic identities and standard p-adic Hodge correspondences).
Assumptions & free parameters
assumptions (1)
- domain assumption p-adic Hodge theory applies to one-dimensional formal groups of height one over finite extensions of Q_p
Cite this review
Pith. "Pith review of Integrality of height-one formal groups." pith.science (2026). https://pith.science/paper/R4Y4JXRV
@misc{pith2026260625726,
author = {Pith},
title = {Pith review of: Integrality of height-one formal groups},
year = {2026},
howpublished = {\url{https://pith.science/paper/R4Y4JXRV}},
note = {Machine review of arXiv:2606.25726}
}
abstract
Let $K$ be a finite extension of $\mathbb{Q}_p$. We prove that a one-dimensional formal group law over $K$ has integral coefficients if and only if its multiplication-by-$n$ endomorphisms have integral coefficients for all integers $n$, in the height-one case, i.e. when the multiplication by $p$ has Weierstrass degree $p$. The proof uses some $p$-adic Hodge theory.
Figures
Reference graph
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Reviewed June 25, 2026 · model on record in the stance chip above.
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