Algebraic Semigroups are Strongly {π}-regular
classification
🧮 math.AG
math.GR
keywords
algebraicregularsemigroupstronglybelongsdefinedexistsfield
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Let $S$ be an algebraic semigroup (not necessarily linear) defined over a field $F$. We show that there exists a positive integer $n$ such that $x^n$ belongs to a subgroup of $S(F)$ for any $x \in S(F)$. In particular, the semigroup $S(F)$ is strongly {\pi}-regular.
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