On absolutely normal numbers and their discrepancy estimate
classification
🧮 math.NT
cs.OH
keywords
absolutelydiscrepancynormalnumbersrealalmostbaseconstruct
read the original abstract
We construct the base $2$ expansion of an absolutely normal real number $x$ so that, for every integer $b$ greater than or equal to $2$, the discrepancy modulo $1$ of the sequence $(b^0 x, b^1 x, b^2 x , \ldots)$ is essentially the same as that realized by almost all real numbers.
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