REVIEW 5 minor 35 references
Taking rational numbers at random
T0 review · 0 major / 5 minor · reviewed 2026-08-14 · deepseek-v4-flash
Pith's one-line read Rationals in $[0,1]$ admit a limiting equiprobable draw: single points get probability zero, intervals get their length.
desk verdict Correct but elementary: the main limit theorem is a standard triangular-array weak convergence result, delivered cleanly but with two sloppy example conditions and a missed totient identity in Section 7. read the letter →
The pith
A machine-rendered reading of the paper's core claim, the machinery that carries it, and where it could break.
The reading
What carries the argument
The load-bearing device is representing the random rational as a ratio $Q=N/M$, where $M$ selects a denominator and $N$ is conditionally uniform on $\{0,1,\ldots,M\}$. For a fixed irreducible $q=n/m$, the probability of $q$ is the sum over all multiples $\ell$ of the denominator $m$ of $P\{M=\ell m\}/(\ell m+1)$; the proof controls this sum by the expectation $\mu_k=E[1/M_k]$. The flattening condition $s_k\ln k\to 0$ forces $\mu_k\to 0$ through the harmonic-number bound, and this single decay estimate is what makes atom probabilities vanish and interval probabilities converge to $b-a$. Floor-function identities then write interval probabilities and the cdf as sums over $M$ that are squeezed between $b-a$ and $b-a$ plus a multiple of $\mu_k$.
What would settle it
Take denominators uniform on $\{1,\ldots,k\}$ and compute, for a fixed rational $q=n/m$, the exact atom probability $(1/k)\sum_{\ell=1}^{\lfloor k/m\rfloor}1/(\ell m+1)$; the claim fails if this does not tend to $0$ as $k\to\infty$. Similarly, for a fixed interval $(a,b]$, the finite floor-sum expression for $P\{a<Q\le b\}$ must tend to $b-a$, and a numerical check at $k=10^5$ is already shown in the paper.
Extended reading notes
Core claim
Under the construction $Q=N/M$, with $P\{N=n\mid M=m\}=1/(m+1)$ and denominator distributions $p_m(k)$ whose supremum $s_k$ satisfies $s_k\ln k\to 0$, the paper proves in Proposition 5.2 that $P_k\{Q=q\}\to 0$ for each $q\in\mathbb{Q}_0$ and $P_k\{a<Q\le b\}\to b-a$ for $0\le a<b\le 1$; the cdf converges pointwise to the uniform cdf. The paper stresses that this does not manufacture a uniform distribution on $\mathbb{Q}_0$, because that would violate countable additivity; it is an asymptotic equiprobability in which each rational's individual probability dies out while rationals pooled in any interval carry exactly the interval's length. The variance of $Q$ also converges to $1/12$, matching the uniform law on $[0,1]$.
Load-bearing premise
The whole setup leans on the standard rule that probabilities add up over countably many disjoint events; under that rule no uniform distribution on the rationals can exist, and the asymptotic limit is the only route offered.
Editorial extensions
If this is right
- For any denominator sequence meeting $s_k\ln k\to0$ — finite uniform, geometric with $w\to0$, or Poisson with $\lambda\to\infty$ — the rational-valued variable converges in distribution to the uniform law on $[0,1]$.
- A practical simulation with large fixed $k$ and equiprobable denominators $1,\ldots,k$ gives a sample whose bin frequencies are almost uniform on $[0,1]$, although only finitely many rationals receive positive probability at that finite stage.
- There is no contradiction with the impossibility of an exact uniform distribution: the limiting measure is the Lebesgue uniform law on $[0,1]$, not a measure supported on $\mathbb{Q}_0$.
- The variance formula $V[Q]=1/12+\mu_k/6$ gives a quantitative, finite-$k$ check of how close the draw is to uniformity.
Reading between the lines
- The proof only uses the harmonic bound to force $\mu_k=E[1/M_k]\to0$, so the essential hypothesis is likely that $E[1/M_k]\to0$; the condition $s_k\ln k\to0$ is a sufficient but probably not necessary route to it.
- If one dropped countable additivity and allowed finitely additive probabilities, an exact uniform distribution on $\mathbb{Q}_0$ would exist; the paper's impossibility claim would fail, while its interval-limit result would survive as an approximation theorem for that nonstandard uniform law.
- Connecting the paper's asymptotic-uniform rational draws to the irregular counting function $\nu_m$ could lead to distributions that weight reduced fractions directly, which the paper leaves open.
Signed reviews
Editorial analysis
A structured set of objections, weighed in public.
Referee Report
Summary. The paper proposes a way to assign probabilities to rational numbers in [0,1] by writing Q=N/M, giving M a distribution on the positive integers and, conditional on M=m, taking N uniform on {0,...,m}. The probability of a rational q with irreducible denominator j is then a sum over ℓ of P(M=ℓj)/(ℓj+1). The paper shows that no exact uniform distribution on Q0 exists in the standard countably additive framework, and proves (Proposition 5.2) that for a sequence of denominator laws whose maximal atom s_k satisfies s_k ln k→0, all point probabilities vanish while P(a<Q≤b)→b−a, so the law becomes asymptotically uniform on [0,1]. Examples, closed-form formulas for geometric denominators, a simulation-oriented finite-support construction, and a discussion of sequencing Q0 are included.
Significance. If it holds, the paper gives a clean rigorous sense in which rational numbers in [0,1] can be drawn 'almost uniformly', despite the nonexistence of an exact uniform distribution on a countable set. The construction contains no fitted parameters, and the main derivation is elementary and correct: Lemma 5.1 and Proposition 5.2 are proved by explicit floor-function bounds, and the countable-additivity obstruction in Section 2 is handled honestly. The paper is modest in scope but self-contained, and its central claim is not circular: condition (13) is a genuine hypothesis on the denominator laws. The main weaknesses are local presentation issues in the examples and in the sequencing remarks.
minor comments (5)
- [Section 5, examples after (13)] For the geometric family, condition (13) requires w_k ln k→0, and for the Poisson family it requires λ_k/(ln k)^2→∞. The text says only that w_k is infinitesimal and λ_k is divergent, which is not sufficient; for instance w_k=1/ln k or λ_k=ln k satisfies those weaker statements but violates (13). Please state the correct rate conditions explicitly.
- [Lemma 5.1] The assertion that R_k is an infinitesimal remainder is correct but not justified in the proof. It follows immediately because for m>k one has 1/m≤1/k, so R_k≤(1/k)∑_{m>k}p_m(k)≤1/k; adding this one-line argument would make the proof complete.
- [Proposition 5.2, proof of (16)] The displayed inequality x−xμ_k < F_Q(x) < x+(1−x)μ_k is not strictly true at x=1, where F_Q(1)=1 and the right-hand side equals 1. Use non-strict inequalities or restrict the displayed line to 0≤x<1 and handle x=1 separately.
- [Section 7, Eq. (19)] The coefficient comparison gives ∑_{d|r}ν_d = r, which means ν_m is exactly Euler's totient φ(m) for m≥2. Identifying ν_m with φ(m) would connect the sequencing discussion to standard number-theoretic facts and simplify the recursive computation. The displayed lines such as 'ν_1/3+ν_2/3=1' are also confusing; they should be phrased as coefficients of powers of z, e.g. (ν_1+ν_2)/3=1 for z^3.
- [Section 6.1, Figure 1] The caption lists fixed values (0.9, 0.5, 0.1, 0.01, 0.001) of w, while Proposition 5.2 concerns a sequence w_k→0. The figure is illustrative, but the text should state explicitly that it does not by itself demonstrate the rate condition (13).
Circularity Check
No significant circularity identified.
full rationale
The paper's central result, Proposition 5.2 with equations (15) and (16), is a proved limit theorem rather than a repackaged input. The construction begins by defining Q=N/M with N conditionally uniform on {0,...,M}, and then imposes the flattening condition sup_m p_m(k) ln k -> 0 on the sequence of denominator distributions. This condition is an explicit hypothesis, not a conclusion or a fitted parameter. The interval-probability limit b-a is derived through floor-function bounds and Lemma 5.1; it is not assumed by the construction. No fitted quantity is later relabeled as a prediction, and the theorem does not rely on any self-citation: the only citation is to a standard reference for harmonic and hypergeometric series. The countable-additivity limitation discussed in Section 2 frames the problem but is not used as a premise in the proof of the asymptotic result. The peripheral issues in the geometric and Poisson examples—where the stated sufficient conditions are weaker than condition (13)—are mathematical or expository caveats, not circularity. Overall, the derivation is self-contained and the limit theorem has genuine mathematical content.
Assumptions & free parameters
free parameters (4)
- Denominator distribution p_m(k)
- Geometric rate w_k
- Poisson rate λ_k
- Finite support size k
assumptions (5)
- domain assumption Probability measures are countably additive; a legitimate distribution on Q0 must have P(Q=q) summing to 1 over all q.
- standard math Every rational q∈[0,1] has a unique irreducible representation q=n/m with gcd(n,m)=1.
- standard math The harmonic numbers H_k grow as ln k and the tail mass of each probability distribution tends to 0.
- standard math All series with non-negative terms may be rearranged and bounded termwise.
- standard math Power series are uniquely determined by their coefficients.
Cite this review
Pith. "Pith review of Taking rational numbers at random." pith.science (2026). https://pith.science/paper/Z4Q5UMZ6
@misc{pith2026190806944,
author = {Pith},
title = {Pith review of: Taking rational numbers at random},
year = {2026},
howpublished = {\url{https://pith.science/paper/Z4Q5UMZ6}},
note = {Machine review of arXiv:1908.06944}
}
abstract
We outline some simple prescriptions to define a distribution on the set $\mathbb{Q}_0$ of all the rational numbers in $[0,1]$, and we then explore both a few properties of these distributions, and the possibility of making these rational numbers asymptotically equiprobable in a suitable sense. In particular it will be shown that in the said limit -- albeit no uniform distribution can be properly defined on $\mathbb{Q}_0$ -- the probability allotted to a single $q\in\mathbb{Q}_0$ asymptotically vanishes, while that of the subset of $\mathbb{Q}_0$ falling in an interval $[a,b]$ goes to $b-a$. We finally give some hints to completely sequencing without repetitions the numbers in $\mathbb{Q}_0$ as a prerequisite to the laying down of more distributions on it
Figures
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Reviewed August 14, 2026 · model on record in the stance chip above.
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