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There is no triangulation of the torus with vertex degrees 5, 6, ..., 6, 7 and related results: Geometric proofs for combinatorial theorems

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arxiv 1207.3605 v2 pith:ZFLF6S4S submitted 2012-07-16 math.CO math.GT

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keywords torustheoremresultstheretriangulationverticescannotcone
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There is no 5,7-triangulation of the torus, that is, no triangulation with exactly two exceptional vertices, of degree 5 and 7. Similarly, there is no 3,5-quadrangulation. The vertices of a 2,4-hexangulation of the torus cannot be bicolored. Similar statements hold for 4,8-triangulations and 2,6-quadrangulations. We prove these results, of which the first two are known and the others seem to be new, as corollaries of a theorem on the holonomy group of a euclidean cone metric on the torus with just two cone points. We provide two proofs of this theorem: One argument is metric in nature, the other relies on the induced conformal structure and proceeds by invoking the residue theorem. Similar methods can be used to prove a theorem of Dress on infinite triangulations of the plane with exactly two irregular vertices. The non-existence results for torus decompositions provide infinite families of graphs which cannot be embedded in the torus.

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  1. Which Holonomy Signatures Are Realizable? A Complete Answer for Closed Surfaces

    math.GT 2026-08 accept novelty 8.0 of 10

    All but five explicit holonomy signatures are realizable on closed surfaces; the five are three torus cases (no cones with nontrivial holonomy, (3π/2,5π/2), (π,3π) with holonomy 2Z4) and two genus-two cases (6π and (3...

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