e_130231
plain-language theorem explainer
At multi-index (1,3,0,2,3,1) the folded midpoint numerator equals eight times the explicit integer kernel. Gravity analysts assembling the 4D Regge exact midpoint M2 TT identity cite this as one of 256 kernel cells. The proof is a single decide on closed integer arithmetic.
Claim. For indices $(a,b,c,d,i,j)=(1,3,0,2,3,1)$ in $(\mathrm{Fin}\,4)^6$, the folded coupling numerator equals eight times the explicit kernel value: $N(1,3,0,2,3,1)=8\,Z(1,3,0,2,3,1)$.
background
This module is chunk 7 of a 256-cell kernel certification that the midpoint numerator equals eight times an explicit integer table on every sextuple of Fin 4 indices. The setting is the 4D Regge exact midpoint analysis of the M2 TT identity in the gravity stack.
The numerator $N=\mathrm{m2Num}$ is defined by folding a fixed coupling list and summing a local contribution at $(a,b,c,d,i,j)$. The table $Z=\mathrm{explicitZ}$ is a pattern-matched integer function on the same six indices (sample values include $4$, $-2$, and so on). The claim under audit is one concrete cell of $N=8Z$.
Upstream, both $N$ and $Z$ live in the kernel certificate module; downstream assembly will quantify over all $4^6$ cells by fin_cases.
proof idea
One-line kernel decision: by decide. Both sides reduce to concrete integers once the six Fin 4 arguments are fixed, so the equality is a closed arithmetic fact with no lemmas beyond evaluation of m2Num and explicitZ.
why it matters
Feeds the universal identity m2Num_eq_eight_explicitZ, which states $\forall a,b,c,d,i,j,, N(a,b,c,d,i,j)=8Z(a,b,c,d,i,j)$ and is proved by exhausting all six Fin 4 coordinates. That assembler is the bridge from 256 decide-chunks to a single quantified certificate used in the Regge exact midpoint M2 TT identity pipeline.
In the Recognition gravity analysis this cell-level equality is pure bookkeeping: it locks the discrete coupling numerator to the explicit kernel so later continuum or continuum-limit arguments can quote a fully discharged integer identity rather than an open fold. No forcing-chain landmark (T5–T8) is at stake here; the stake is mechanical completeness of the 4D midpoint kernel.
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